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q=mass * Cs * delta T

= 0.25kg * 4.18 * (85-10)

=78J

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14y ago
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12y ago

187.5 calories

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78,375 J

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Q: How much heat is required to raise the temperature of 250 grams of water from 10 degrees to 85 degrees celsius?
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Related questions

What would be the final temperature when 250 grams of water at 100 degrees celsius is mixed with 525 grams of water at 30 degrees celsius?

The temperature would be that of water's boilng point od 100 degrees


How much energy is required to raise 21kg of water by 2 degrees Celsius?

21 Kg = 2100 grams to rise the temperature of this amount of water by 2 degrees Celsius you need 2*2100 = 4200 calories or 17572.8 Joules.


What is the total heat loss if you have 18 grams of aluminum and the temperature changes from 64 degrees Celsius to 48 degrees Celsius?

Approx 4974 Joules.


How many calories are required to raise 8 grams of water 7 degrees Celsius?

700


Is 50 grams 96 degrees Celsius 148 meters or 259 liters a measurement of volume?

Liters measure volume. Grams are a measure of mass, degrees Celsius are a measure of temperature, and meters are a measure of length.


If 75 grams of water at 30 degrees Celsius absorbs 900 calories what will be the new temperature?

105C


What is the density of warm water cold water and ice?

Density of ice at 0 degrees Celsius is 916.8 grams per cubic centimeter or milliliter. The density of fresh water is dependant on the temperature: At 3.98 degrees Celsius the density is 0.999975 grams per milliliter. At 100 degrees Celsius the density is 0.958.35 grams per milliliter.


How much heat is required to increase the temperature of 203 grams of water from 20.1 Celsius to 51.3 Celsius?

2.65 x 10^4 J


How many calories are required to heat 38.2 grams of aluminum from 102 degrees celsius to 275 degrees celsius?

Specific heat for aluminium = 0.214 Heat required = 38.2 x 0.214 x (275 - 102) = 1414.24 calories


How many calories of heat would it take to raise the temperature of 256 grams of water from 20 degrees to 99 degrees?

A calorie is the amount of heat you need to raise the temperature of one gram of water by one degree Celsius. Assuming you are raising the temperature of the water from twenty degrees Celsius to ninety-nine degrees Celsius, it would take 20,000 calories. To calculate this, subtract 20 from 99. This is the amount of degrees you need to raise the temperature of the water by. Then multiply that number by 256, the amount of water in grams. You should get 20,244 calories. In significant digits, your answer should be 20,000 calories.


How much heat is required to raise the temperature to 5.0 mL of water from 2.50 degrees Celsius to 75 degrees Celsius?

Density = grams/ml 1.00 g/ml = X g/5.0 ml = 5.0 grams water ============== q(joules) = mass * specific heat * change in temp. q = (5.0 grams)(4.180 J/gC)(75 C - 2.50 C) = 1515.25 Joules ---------------------------------/4.184 = 362 calories -------------------


Is gram used to measure the temperature in the metric system?

No, grams are unit of mass, not temperature. Temperature is measured in °C (degrees celsius) or for scientific work in 'K' K = °C + 273.15