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A 2 input NAND gate requires 4 NOR gates.A 3 input NAND gate requires 5 NOR gates.A 4 input NAND gate requires 6 NOR gates.etc.
I suppose so. If a three input NAND is used as a two input device, the third input can be viewed as an inhibit input. Also some NAND devices can be "3 stated" where the output goes to a high impedance.
Short both the inputs, if '0' is given as the input output will be '1' and if '1' is given as a input the output will be '0'
All other logic gates can be made using XOR and XNOR, but to get NOT, you need to do (input) XOR 1 or (input) XNOR 0, but with NAND, you don't need 1: (input) NAND (input).
When the two input terminals of a NAND gate are short circuited, it acts as a NOT gate.
A: NAND implies not and to be true both input must be hi or true <> There are two flavors of NAND gate. The positive input/negative output NAND will have a low output if and only if both inputs are high. The negative input/positive output NAND will have a high output if and only if both inputs are low.
A binary flip flop is a collection of 4 NAND gates arranged in specific circuit to allow it preserve state. The first two NAND gates use an external voltage as their first input and themselves as their second input; where as the second set of NAND gates use the first pair of gates output as their first input, and themselves as their second input.
NOT Gate
The 7400, and its variations, is a quad two input NAND gate.
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The 7400, and its variations, is a quad two input NAND gate.
when the two inputs are shorted, a NAND gate acts like a NOT gate. hence AND = NAND + NOT For OR gate, inverse both the inputs before connecting them to a NAND gate. So three NAND gates would be needed.