It is a 3 byte instruction, with one byte for opcode and the other two for the 16bit address. It takes four machine cycles (one to fetch opcode, one to fetch lower order address, one to fetch higher order address and another one to fetch the data from the memory)... i.e. it takes 13 time states to perform the LDA instruction
12
12
AnswerThe internal is located inside your computer. If your running Windows, the time it keeps is display on the lower right side of the screen. An external clock is usually located on another system and can be accessed with software. You can get software to sync your internal clock to that other system. The National Institute for Science and Technology (NIST) hosts a clock that many computer users and businesses sync to.Wow...can that answer be any more wrong?Internal and External clocks are NOT referring to the "time of day" type clocks, they refer to the internal processor clock cycle or an external clock source. The clock cycle of a processor is the time it takes for the processor to execute a data instruction (very basic explanation there) and is measured as the speed of a processor, like a 2.6gHz processor can execute 2.6 billion clock cycles per second.Now this is somewhat misleading as the processor speed itself is probably only 400MHz, but using an External Multiplier (clock multiplier, external clock), you increase the total amount of data the processor can execute in one clock cycle.This is a VERY basic example and I don't have time to really go deep, so it's best to search for a more concise answer if you really require one.
The difference between 2.66 dual core processor, and 64-bit dual core processor, is really two different processor specifications. 2.66 is actually 2.66Ghz, which is the clock speed of the processor. The clock speed tells you how many times the processor can execute instructions per second. A dual core processor is a processor with two cores on one die. This can be thought of as having two processors in one. The bit specification of a processor tells you how many binary instructions a processor can execute per clock cycle. Most processors today are 32-bit (32 binary instructions per clock cycle) or 64-bit (64 binary instructions per clock cycle). More RAM can be used with a 64-bit processor. A 32-bit processor is limited to addressing 4 Gigabytes of RAM, while a 64-bit process can address (theoretically) 16 Exabytes of RAM.
The number of instructions that can execute in one second in the 8086 microprocessor is highly dependent on clock speed, memory wait time, and instruction complexity mix, but the generally accepted performance factor is 0.33 MIPS (Million Instuctions per Second) at a clock speed of 4.77 MHz.
Twice in a 24 hour cycle at 3:00.
one ghz represent 1 billion cycle per second.....the speed of microprocessor called clock speed ...each computer instruction require a fixed number of cycles...so clock speed determine how many instruction per second the microprocessor can execute....
The MOV A,B instruction requires 1 machine cycle and 4 T-states, 3 to fetch the opcode, and 1 to decode/execute it.
2 big juicy runs could make a clock run for 5 month but 2 regular ones would make a clock run for 1 month
The answer is 1,2,3, or 6
Many manufacturers publish the speed of the FSB in MHz, but often do not use the actual physical clock frequency but the theoretical effective data rate (which is commonly called megatransfers per second or MT/s). This is because the actual speed is determined by how many transfers can be performed by each clock cycle as well as by the clock frequency. For example, if a motherboard (or processor) has a FSB clocked at 200 MHz and performs 4 transfers per clock cycle, the FSB is rated at 800 MT/s.
720 degrees