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How many clock pulse are need to shift one byte of data from thew input to output of a 4 bit shift register?
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How can IC 74190 will give output freq as 50Hz?
The 74190 is an up/down decade counter. Counters use frequency division to achieve a counting sequence. To answer your question, it depends on the input frequency. The Qa output will divide the clock input by 2 so if the input is 100Hz, Qa's output is 50Hz. Since this is a decade (0 to 9, or truncated sequence) counter and not a binary (0 to 15, or full sequence) counter, the outputs Qb, Qc and Qd divide the input but their outputs are not symmetrical (equal time high and time low). Qb and Qc produce 2 pulses for every 10 input pulses, therefore divide the input clock by 5. Qd produces one output pulse for every 10 input pulses, therefore divides the input by 10. The easiest way to visualize this is to write out the binary count in column format, starting at 0000 and ending at 1001, and looking at each of the output patterns. To produce the 50Hz output, assuming you are not concerned over symmetry: -input clock 100Hz for 50 Hz on Qa -input clock 250Hz for Qb or Qc output of 50Hz -input clock 500Hz for Qd output of 50Hz
Why does a d-type flip flop need a transition gate on its clock input?
The D Flip-Flop takes the logic level of 'Data' to the output only on the rising edge of the clock pulse.Without the transition gate: Since the clock pulse is a square wave (and is high for half a cycle, and low for the other half), the logic level at 'Data' could change while the clock pulse is high, causing the output to change before the next rising edge. This is not how a flip-flop operates.The transition gate prevents this by converting the clock pulse into a very short 'blip' of a few nanoseconds, starting at the rising edge of the clock pulse, repeating on the next cycle. This means there is only a very small window where the clock is high, and the logic level at 'Data' can be taken to the output.
What is pulse and digital circuit?
pulse or clock pulse in a commonly used term and a clock pulse is generally a square wave where the higher voltage represents digital logic '1' and the lower voltage represents the digital logic '0' and the frequency of this wave is manually adjusted depending on our requirement i.e either we need a very fast responsive system or a slow one digital circuit :- it is similar to electric circuit where the components are placed in a particular manner to get the desired output. on seeing the problem statement first of all we estimate the no. of input as well as no.of outputs and we would try to draw the truth table basin on the given conditions and from the truth table we would derive the relation between output variables and input variables or in other words we express the output variables as he function of input variables and finally we use different gates to connect inputs to get the required output
Why a parallel counter is capable of faster operation than a ripple counter?
The parallel counter incorporates carry lookahead circuits so that all flip-flops in the counter change in sync with the clock pulse. The ripple counter each flip-flop output is the clock for the next flip-flop, causing the most significant bit of the counter to settle only after a long delay time from the input clock pulse.
What are the basic applications of j flip flop?
This flip-flop toggles (Q changes state) on the negative going edge of the clock pulse. T acts as an ENABLE / INHIBIT control. Q will only toggle on the negative edge of the clock pulse, when T is high. Below is shown a D type flip-flop connected as a toggle type. On each clock pulse positive going edge, Q will go to the state bar Q was before the clock pulse arrived. Remember that bar Q is the opposite level to Q. Therefore Q will toggle.
What is the output from an AND gate if the two inputs each carry a pulse?
The output from an AND gate is TRUE if both inputs are TRUE. If each input is given a pulse, the output will pulse, but only for the time that the two input pulses overlap each other in time. If the input pulses do not overlap, the output will do nothing.This answer assumes that the input pulses are from FALSE to TRUE and back to FALSE. In the reverse case, the output will pulse whenever either input is pulsed and, if the inputs overlap in time, the output will simply be one longer pulse.
What does ic 7475 do?
The 7475 is a TTL MSI circuit that contains four D latches, it is also known as 'quad bistable latch.' The 7475 is mostly used for temporary storing 4-bit nibbles of data. Any length of data can be stored by using more than one 7475 chip. When all four clock input pins connected to logic high clock pulse, input data is loaded into the D latches(each latch is D Flip-Flop) and appears at the Q output and remains there. After clock pulse goes logic low, the output at Q and Q' still holds input data till clock pulse changes it logic state back to 'High' and input data is changed.
How can IC 74190 will give output freq as 50Hz?
The 74190 is an up/down decade counter. Counters use frequency division to achieve a counting sequence. To answer your question, it depends on the input frequency. The Qa output will divide the clock input by 2 so if the input is 100Hz, Qa's output is 50Hz. Since this is a decade (0 to 9, or truncated sequence) counter and not a binary (0 to 15, or full sequence) counter, the outputs Qb, Qc and Qd divide the input but their outputs are not symmetrical (equal time high and time low). Qb and Qc produce 2 pulses for every 10 input pulses, therefore divide the input clock by 5. Qd produces one output pulse for every 10 input pulses, therefore divides the input by 10. The easiest way to visualize this is to write out the binary count in column format, starting at 0000 and ending at 1001, and looking at each of the output patterns. To produce the 50Hz output, assuming you are not concerned over symmetry: -input clock 100Hz for 50 Hz on Qa -input clock 250Hz for Qb or Qc output of 50Hz -input clock 500Hz for Qd output of 50Hz
What are clock inputs?
A clock input is a regular periodic pulse that can be used as a trigger to sequence timing-important activities.
Why does a d-type flip flop need a transition gate on its clock input?
The D Flip-Flop takes the logic level of 'Data' to the output only on the rising edge of the clock pulse.Without the transition gate: Since the clock pulse is a square wave (and is high for half a cycle, and low for the other half), the logic level at 'Data' could change while the clock pulse is high, causing the output to change before the next rising edge. This is not how a flip-flop operates.The transition gate prevents this by converting the clock pulse into a very short 'blip' of a few nanoseconds, starting at the rising edge of the clock pulse, repeating on the next cycle. This means there is only a very small window where the clock is high, and the logic level at 'Data' can be taken to the output.
How does pulse transformer work?
i exactly donot know the working..but i know the basic thing it does..whatever input signal is given to it..it creats a dV/dt output of the input signal... example say you are given input as a rectangular pulse wave...then at the output you would recieve a spike....
What is pulse and digital circuit?
pulse or clock pulse in a commonly used term and a clock pulse is generally a square wave where the higher voltage represents digital logic '1' and the lower voltage represents the digital logic '0' and the frequency of this wave is manually adjusted depending on our requirement i.e either we need a very fast responsive system or a slow one digital circuit :- it is similar to electric circuit where the components are placed in a particular manner to get the desired output. on seeing the problem statement first of all we estimate the no. of input as well as no.of outputs and we would try to draw the truth table basin on the given conditions and from the truth table we would derive the relation between output variables and input variables or in other words we express the output variables as he function of input variables and finally we use different gates to connect inputs to get the required output
What is d flip flop?
The D flip-flop has a D and Clock input, and a Q (and sometimes Q/) output. The D input is copied to the Q (and, inverted, Q/) output on the specified edge of Clock.Its like a J-K flip-flop where K is driven with the inverted value of J.ANSWER: D stands for data it it will transfer the data with a clock control inputd type flip flop is a flip flop whose output is a function of the input which appeared one pulse earlier. Also known a d type flip flop.
Why a parallel counter is capable of faster operation than a ripple counter?
The parallel counter incorporates carry lookahead circuits so that all flip-flops in the counter change in sync with the clock pulse. The ripple counter each flip-flop output is the clock for the next flip-flop, causing the most significant bit of the counter to settle only after a long delay time from the input clock pulse.
How a ripple counter works?
Clock is propagated from one T or JK flip flop to another hence it works. A ripple counter works by the following principle. A clock pulse is applied to the first flip flop and the output of the first flip flop acts as the clock input to the second flip flop and the sequence continues in that order.
Is CPU an input device?
No not really, it's the brain. CPU is the Central processing Unit which receives input via input devices like keyboard, mouse , scanner, mic etc. It's main job is to process the input and send to the relevant o/p device. It controls the flow and process of instructions, in time with a clock pulse. It needs to handle both input and output of binary data.
What will be the output when a square wave is the input of the differentiater?
If you use a square wave as input to an integrator circuit, the output will be a triangle wave.
