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How many different permutations can be made of the letters of the word 'dependent'?
Wiki User
∙ 11y ago
About 68, using the Scrabble dictionary:
1 de
2 dee
3 deed
4 deen
5 deep
6 deepen
7 deet
8 den
9 dene
10 denet
11 denned
12 dennet
13 dent
14 dented
15 depend
16 dependent
17 ed
18 ee
19 een
20 en
21 end
22 ended
23 ene
24 epee
25 et
26 eten
27 ne
28 ned
29 nee
30 need
31 needed
32 neep
33 nene
34 nep
35 net
36 nete
37 pe
38 ped
39 pee
40 peed
41 peen
42 peened
43 pen
44 pend
45 pended
46 pendent
47 pene
48 pened
49 penne
50 penned
51 pent
52 pentene
53 pet
54 te
55 ted
56 tee
57 teed
58 teen
59 teend
60 teended
61 teene
62 teened
63 ten
64 tend
65 tended
66 tene
67 tenne
68 tepee
Wiki User
∙ 11y ago
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How many different three letter permutations can be from the letter in the word clipboard?
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How many different 4 letter permutations are there for the letters in the word toolroom?
120 four letter permutations if you don't allow more than one 'o' in the four letterarrangement.209 four letter permutations if you allow two, three and all four 'o'.1.- Let set A = {t,l,r,m,}, and set B = {o,o,o,o}.2.- From set A, the number of 4 letter permutations is 4P4 = 24.3.- 3 letters from set A give 4P3 = 24, and one 'o' can take 4 different positions in theword. That gives us 24x4 = 96 four letter permutations.4.- In total, 24 + 96 = 120 different four letter permutations.5.- If the other three 'o' are allowed to play, then you have 2 letters from set A thatgive 4P2 = 12 permutations and two 'o' can take 4C2 = 6 position's, giving 12x6 = 72four letter permutations.6.- One letter from set A we have 4P1 = 4, each one can take 4 different positions, therest of the spaces taken by three 'o' gives 4x4 = 16 different permutations.7.- The four 'o' make only one permutation.8.- So now we get 72 + 16 + 1 = 89 more arrangements adding to a total of 89 + 120 = 209 different 4 letter arrangements made from the letters of the word toolroom.[ nCr = n!/((n-r)!∙r!); nPr = n!/(n-r)! ]
How many arrangements can be made with the letters spineless?
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How many license plates can be made using three digits and three letters without repetition and alternating letters and digits?
If it alternates and you start with a letter, then there are 11,232,000 permutations. Then if you start with a number and alternate, there are another 11,232,000 permutations, for a total of 22,464,000 permutations. If you exclude the letters I, S, B, and O (because they look kind-of like 1, 5, 8, & 0 - kind-of important on license plates) then you are down to 6,652,800 & 13,305,600 respectively.
How many different passwords can be made out of 4 different uppercase letters?
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How many permutations are in the word arithmetic?
10! permutations of the word "Arithmetic" may be made.
How many permutations of 5 numbers can be made from the numbers 1 to 90?
There are 5,273,912,160 permutations of 5 numbers out of 90.
How many different numbers can be formed with the digits 345?
Assuming you mean permutations of three digits, then the set of numbers that can be made with these digits is: 345 354 435 453 534 543 There are six possible permutations of three numbers.
