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Assuming each base is in equal amounts, the answer is 65,536.

There are four bases possible for each spot. So that means there are 4 choices in the first spot, 4 in the second, 4 in the third, etc. You multiply each spot: 4 × 4 × 4 ••• 4 all the way to eight. To simplify, 48 or 65,536.

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This DNA strand consists of eight pairs of nitrogenous base.How many different sequences of eight base can you make?

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Q: How many different sequences an you make with 8 bases?
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