56-2=54
Your answer is 54.
~JM Chem 130 2012~
Ba2+ ion has a total of 56 electrons. Barium (Ba) has 56 electrons in its neutral state, and when it loses two electrons to become Ba2+, it now has 54 electrons remaining.
Barium (Ba) has an atomic number of 56, which means it has 56 electrons in a neutral atom. The "2" you mentioned likely refers to the charge on the barium ion (Ba2+), which means it has lost two electrons, resulting in 54 electrons in the Ba2+ ion.
The H+ ion has no electrons.
The barium ion has a charge of +2. It loses two electrons to become positively charged.
When a barium atom loses two electrons, it forms a Ba2+ ion. The ion will have a +2 charge and a stable electron configuration similar to a noble gas, which increases its stability. The ion will also have a smaller radius compared to the neutral atom due to the loss of electrons.
A Co3+ ion has lost three electrons from its neutral state, so it has 23 electrons.
When a barium atom forms an ion, it loses two electrons to achieve a stable octet configuration like a noble gas. This results in the formation of a Ba2+ ion with a 0 oxidation state.
I believe that would be Barium nitrate or Ba(NO3)2
An Mg2+ ion has lost two electrons, resulting in a total of 10 electrons. Magnesium normally has 12 electrons but when it forms a 2+ ion, it loses two electrons.
The formula for the barium ion is Ba^2+. It has lost two electrons to achieve a full outer shell and a stable electronic configuration.
No. Barium is a Group 2 element, and as such will lose its two valence electrons to form a Ba2+ ion when forming an ionic compound.
barium will lose two electrons to form an ion with a plus 2 charge. Thus, the resulting ion in reactions of barium is Ba2+.Read more: http://wiki.answers.com/What_type_of_ion_would_barium_form_if_group_1_loses_one_electron_to_form_ions_with_a_1_plus_charge#ixzz17vdoXVSf