there are 54 electrons in Ba 2+. as the atomic no. of Ba is 56, so when it loses two of its electrons..
there are 54 electron left..
When a barium atom forms an ion, it loses two electrons to achieve a stable octet configuration like a noble gas. This results in the formation of a Ba2+ ion with a 0 oxidation state.
Two electrons are donated by Barium to an oxidant (nonmetal, eg. O2) by which barium gets oxidised.Ba --> Ba2+ + 2e-This is because Ba is in group 2 of the periodic system, belonging to the 'earth alkali' metals and so it has 2 electrons (2e-) in its valency (or outer) shell (2,8,18,18,8,2). Hence Ba2+ configuration is (2,8,18,18,8,-), with an empty (-) 6th shell (the 'P' shell) like Xenon.
barium will lose two electrons to form an ion with a plus 2 charge. Thus, the resulting ion in reactions of barium is Ba2+.Read more: http://wiki.answers.com/What_type_of_ion_would_barium_form_if_group_1_loses_one_electron_to_form_ions_with_a_1_plus_charge#ixzz17vdoXVSf
Xe, Ba2+
I believe that would be Barium nitrate or Ba(NO3)2
Ba2+ ion has a total of 56 electrons. Barium (Ba) has 56 electrons in its neutral state, and when it loses two electrons to become Ba2+, it now has 54 electrons remaining.
56-2=54 Your answer is 54. ~JM Chem 130 2012~
Neither..they both have approximately the same weight as electrons are virtually weightless.bt the ba2 plus wud have to combine with another element for charge stability and the compound it forms shud be heavier than ba.
When a barium atom loses two electrons, it forms a Ba2+ ion. The ion will have a +2 charge and a stable electron configuration similar to a noble gas, which increases its stability. The ion will also have a smaller radius compared to the neutral atom due to the loss of electrons.
[Xe] Normally the electronic configuration for Barium would be [Xe] 6s2, but since you want it for Ba2+, you're missing two electrons. You get rid of the 6s2 and get [Xe].
The oxidation state of Ba2 is 2.
When a barium atom forms an ion, it loses two electrons to achieve a stable octet configuration like a noble gas. This results in the formation of a Ba2+ ion with a 0 oxidation state.
The barium ion has a charge of +2. It loses two electrons to become positively charged.
exam date seet ba2
The reaction between SO42- and Ba2+ forms BaSO4. The chemical formula is BaSO4.
There is no noble gas with the same electronic configuration as the element barium (Ba). But Ba2+ ion and the noble gas xenon (Xe) will have the same number of electrons (54 electrons each).
The formula for the barium ion is Ba^2+. It has lost two electrons to achieve a full outer shell and a stable electronic configuration.