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Electrons do have charge. The chare of an electron - 1.602*10-19 C
An electron has a charge of about 1.6 x 10-19 Coulombs (the fundamental or elementary charge)So we can use a proportion and cross multiply it to find this out.Let x = # of electrons( 1 electron / 1.6 x 10-19 C) = ( x / 1 C )= 1/1.6 x 10-19 electrons = 1019/1.6electrons1019/1.6electrons = 6.25 x 1018 electrons(6250000000000000000 electrons)If you wanted to say that number:six quintillion, two hundred fifty quadrillion electrons
There are 31.25* 10^18 electrons in 5 c0ulombs
Just plug it into the Current formula. An ampere is one coulomb / second and the formula is I = q / t. Otherwise q / t = 1 amp ; let t = 1 sec q = 1 C ; The charge of an electron is 1.6 x 10^-19 C but is follows that there are 6.25 x 10^18 electrons in one second (inverse of charge). Remember that the amount of electrons in an ampere is dependent on time!
Look up the charge of an electron, then divide 80 microcoulombs by that charge. Note that "micro" means a millionth. Also note that a coulomb is a positive charge, whereas the electron has a negative charge.
One electron has - 1.602 X 10 -19 coulomb of charge. So disregarding the negative sign....., 2.86 C/1.602 X 10 -19 C = 1.79 X 1019 electrons in that much charge. ============================
1.602 x 10-19 C is the charge because of one electron So 12 C will be due to 12 / 1.602 x 10-19 = 7.49 x 10 19 electrons.
Each electron have a charge of 1.6 * 10 ^ ( -19) c so by dividing 6.8/(1.6 * 10 ^ -19) 4.25 * 10 ^ 19 electrons are required
Electrons do have charge. The chare of an electron - 1.602*10-19 C
Each electron has a charge of 1.602*-19 C, so it would take (6*10^-6)/(1.602*10^-19)=3.745*10^13 of them to produce a charge of 6*10^-6 C.
To calculate this you'll have to divide the amount of negative (electron) charge (-0.80 C) by the charge of one electron (-1.06*10-19 C/electron) (which is a so called 'table' value, measured by an internationally approved scientific method):you'll get 0.800 (C) / 1.06*10-19 (C/electron)= 6.03*10+18 electrons
The measurement of charge is not correct as it is not the integral multiple minimum charge(that is 1.6 x 10-19C). However , there is your answer Charge on a body is given by,q = ne Therefore , required no. of electrons,n = q/e = 3.45 x 10-17 /1.6 x 10-19 = 2.15625 x 102
An electron has a charge of about 1.6 x 10-19 Coulombs (the fundamental or elementary charge)So we can use a proportion and cross multiply it to find this out.Let x = # of electrons( 1 electron / 1.6 x 10-19 C) = ( x / 1 C )= 1/1.6 x 10-19 electrons = 1019/1.6electrons1019/1.6electrons = 6.25 x 1018 electrons(6250000000000000000 electrons)If you wanted to say that number:six quintillion, two hundred fifty quadrillion electrons
There are 31.25* 10^18 electrons in 5 c0ulombs
16/(1.6*10^-19)=10^20 electrons
The measurement of charge is not correct as it is not the integral multiple minimum charge(that is 1.6 x 10-19C). However , there is your answer Charge on a body is given by,q = ne Therefore , required no. of electrons,n = q/e = 3.45 x 10-17 /1.6 x 10-19 = 2.15625 x 102
Number of excess electrons = Q/E = 10/-1.6x10^-19 = 6.24x10^19