Fluorine belongs to the 7th Group of the Periodic Table - the halogens. It has --> 9 Protons 10 Neutrons 9 electrons in the atomic state.
Also - it's oxidation state (valency) is (1-) or (7+) It has 7 electrons in it's outer most shell.
there are 9 electrons in the element fluorine.
The atomic number of fluorine is 9, so there are 9 protons and 9 electrons.
There are nine electrons in a fluorine atom.
1s2 2s2 2p5
as the atomic number is 9.so 9 electrons are distributed in different sub shells
Nine electrons in two shells: 2 and 7 resp. in the 1st and 2nd.
Remember: number of shells is the number (name) of the period in the periodic system.
Fluorine has 9 protons.
9
8
Flourine and Cholrine have similar properties because they have the same number of electrons in outmost shell (7). Each group has similar properties because their amount of valence electrons (electrons in the outmost shell) can only support bonding with certain elements.
Yes! One of the reasons is that Flourine has 7 valence electrons, meaning that it 'wants' to accept an electron (oxidizing) from the reducing agent more than Oxygen 'wants' to.
Yes, fluorine is a nonmetal.
Fluorine... by far. Its so electronegative that it will never form double bonds, even if they would make sense by the octet rule. BF3 is a really good example of this
Assuming that "flourine" is intended to be "fluorine", the answer is no. Both carbon and fluorine are unlikely to be electron donors and therefore form a covalent bond instead, so that both of these non metals can share electrons.
A fluorine atom has 9 electrons and it has the only isotope, fluorine-19.
Fluoride-19 has 10 electrons (just to mention it, fluoride is the ion of flourine, so if you meant fluorine, fluorine has 9 electrons).
halogens such as flourine, chlorine, bromine..
Flourine. Neon already has 8 valence electrons. It doesn't want to bond with anything. Flourine needs one more electron.
F-1 (flouride). Flourine has the strongest attraction for electrons of any element, so the oxidation state of -1 is the only one that flourine uses.
Flourine is far more electronegative, meaning it pulls harder on the electrons, making it slightly negative and the sulfur slightly positive.
Fluorine-19 (not "flourine-19) has an atomic number of 9 and therefore has 9 each of protons and electrons. The number of neutrons is found by subtracting the atomic number from the atomic mass number: 19 - 9 = 10 neutrons.
I believe there is 8 electrons in the outer valence
The atomic number determines how many protons and electrons an atom has. Flourine's atomic number is 9 so there are 9 protons and electrons. Energy levels of atoms can only hold a maximum number of electrons per enegery level. The first energy level (s) holds 2 electrons. The second level (p) holds a maximum of 8 electrons because s has two and p has 6. So, Flourine's energy levels would be as follows: 1s2, 2s2 2p5 Energy levels need even pairs to be stable, so Flourine tends to gain only one electron because that is all that is needed for 2p5 to be filled to its maximum capacity. It is easier for an atom to gain one electron than give up 5.
Flourine is part of the Halogen groups
Flourine (atomic number 9) has 9 protons and 9 electrons and 10 neutrons. Of course if it were a trick question than all elements with an atomic number of 9 or greater would hae 9 electrons :)
It has the last electron to fill the p-subshell. Its valence electrons mimic a noble gas, so it is nonreactive.