This most likely refers to CoSO4, or cobalt II sulfate, which contains 3 elements: cobalt, sulfur, and oxygen.
However, capitalization is important in writing chemical formulas, and the lack of capitalization creates some ambiguity.
COSO4, would also contain 3 elements: carbon, sulfur, and oxygen, though this particular configuration is unlikely.
This solution should contain 0.500 grams anhydrous cobalt(II)-sulfate (CoSO4) per litre.When using mono- or heptahydrate, increase the weighted mass by the relevant molar mass ratio.Molar masses:154.996 g/mol CoSO4 (anhydrous)173.01 g/mol CoSO4.H2O (monohydrate) ==> ratio 173/155 = 1.12, so 0.556 g/L281.103 g/mol CoSO4.7H2O (heptahydrate) ==> ratio 281/155 = 1.81, so 0.905 g/L
3 Elements is the Answer
14 elements.
There are about 92 elements in the crust.
The current periodic table contains 118 elements, as of April 2010, but many more may still be discovered.
Cobalt (II) Sulfate
Cobalt tetraoxosulphate (vi) ion
Cobalt tetraoxosulphate (vi) ion
+2
nope weak
Cobalt (II) sulfate.
Cobalt tetraoxosulphate (vi) ion
CoO + H2SO4 --> CoSO4 + H2O
Al(SO4)3 ^That is completely wrong. Al(SO4)3 is aluminum sulfate cobalt ii sulfide is CoS actually you both are wronq. its really CoSO4 <<< cobalt sulfate Wow. He/She was right. Your totally wrong. Cobalt (II) Co^2+ and Sulfide is S^2- So the answer is CoS. Signs cancel themselves out..
This solution should contain 0.500 grams anhydrous cobalt(II)-sulfate (CoSO4) per litre.When using mono- or heptahydrate, increase the weighted mass by the relevant molar mass ratio.Molar masses:154.996 g/mol CoSO4 (anhydrous)173.01 g/mol CoSO4.H2O (monohydrate) ==> ratio 173/155 = 1.12, so 0.556 g/L281.103 g/mol CoSO4.7H2O (heptahydrate) ==> ratio 281/155 = 1.81, so 0.905 g/L
2
118 elements