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Assuming the question refers to torque, then 1 ft-lb = 12 in-lbs. If you have a torque wrench reading inch-pounds, divide by 12 to get foot pounds. Conversely, multiply foot pounds by 12 to get inch pounds. If you want to get a little more technical, then read on. Torque quantifies force applied in a twisting action, such as tightening a bolt with a wrench. The longer the lever arm (distance the force is applied from the point of rotation) the greater the torque. This assumes the force is applied in a direction perpendicular to the lever arm, which is the normal case in practice. Formally, the definition of torque is force multiplied by distance, or force acting perpendicular to the lever arm multiplied by the length of the lever arm. If you are doing something like using a torque wrench on a car, you steady the connection of the wrench to the bolt or nut to make sure the force you are applying is perpendicular to the axis define by the length of the bolt. Then the reading on the torque wrench is an accurate measure of the torque applied to the nut or bolt.
force times length is the dimension for Work or Energy or Torque. Some examples are Newton meters (equivalent to Joules), inch pounds, foot pounds. The pounds are pounds force, not pounds mass.
The question was going along so nicely there, until it got to the very end, and thenshot itself in the foot with "foot pounds"."Foot pounds" is a torque, not a force.-- If you apply 50 pounds of force at the end of the crank, that 50 pounds becomes175 pounds of force at the surface of the 8-inch cylinder, because the mechanicaladvantage of the crank/cylinder arrangement is 28/8 = 3.5 .-- If you apply 50 foot-pounds of torque at the end of the crank, then the force is50 ft-lb/28 inches = 50 lb x 12 in/28 in = 21 3/7 pounds .Now, the same mechanical advantage of 3.5 gives you 75 pounds at the hub.What a difference a unit makes !
an imperial ounce is something i do not know!
1 foot = 12 inches(1 foot) pound = (12 inch) pounds(18 foot) pounds = (18 x 12) = 216 inch pounds
300
600 foot pounds
90 inch - pounds (torque) = 90 / 12 = 7.5 foot pounds (torque)
20nm = 14.751243 foot-pounds.
Torque settings on 1300 Toyota Tazz are torque to 59 foot-pounds, loosen one full-turn. Then, torque 37 foot-pounds and 68 foot-pounds. Torque sequence is 6, 4, 2, 8,7, 3, 1, 5.
65 nm is ~47.94 foot-pounds.
According to the Autozone website : For a 1995 Ford Windstar , 3.8 L V6 engine : The spark plug tightening torque is ( 7 to 15 foot pounds )
The torque setting for the pressure plate on the clutch for an s10 2.2 is 33 foot pounds. The torque for the 4.3 is 29 foot pounds.
18 foot/pounds 18 foot/pounds
100 foot pounds100 foot pounds
== 12-16 Foot pounds (Final torque) Note: to torque bolts & nuts, start in center using crisscross pattern working outward The Head Bolt Torque 65-72 Foot pounds (Final torque) Torque sequence ------------ front | 9 5 1 3 7 | of | 10 6 2 4 8 | engine ------------ Final torque must be reached in 3 equal steps Recheck final torque in sequence The Intake Bolt Torque 23-25 Foot pounds (Final torque) Torque bolts & nuts in numbered sequence --------------- | 5 1 9 11 3 7 | | 6 4 12 10 2 8 | --------------- The Main Bearing Cap Torque 60-70 Foot pounds (Final torque) The Main Bearing Cap Torque 60-70 Foot pounds (Final torque) The Rod Bearing Cap Torque 19-24 Foot pounds (Final torque)
20 foot pounds