1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl
3.6g NaCl x 1mol NaCl/58.443g NaCl x 6.022 x 1023 formula units NaCl/mol NaCl = 3.7 x 1022 formula units NaCl
How many grams of NaCl are present in 8.39x10^22 formula units of NaCl?
The number of formula units of NaCl is 11335.10e17.
1 mole NaCl = 58.443g NaCl = 6.022 x 1023 formula units NaCl 3 x 1025 formula units NaCl x 1mol NaCl/6.022 x 1023 formula units NaCl x 58.443g NaCl/mol NaCl = 2911g NaCl = 3000g NaCl (rounded to 1 significant figure)
Use stoichiometry. 3.5g-> moles 22.99+16+1.0079=39.99 Now 3.5/39.99 = .088 moles of NaOH Now you can use avagadros number 6.022x10^23 .088 moles -> formula units .088/6.022x10^23 You should end up with 1.46x10-25 formula units. Yeah, I know, Chem sucks huh?
4.5 moles NaCl = 4.5000000000001 formula units NaCl *******************2nd Opinion************* 4.5 moles of NaCl would contain 4.5 x (6.02 x 1023) formula units. = 2.7 x 1024 formula units
0,665 moles NaCl is equivalent to 38,86 g.
To find the number of moles in 2.9 x 10^21 formula units of NaCl, you first need to determine the number of moles in 1 formula unit. As NaCl contains one Na+ ion and one Cl- ion, there is 1 mole of NaCl in 2 moles of ions. Then, you can calculate the number of moles in 2.9 x 10^21 formula units by dividing this number by Avogadro's number (6.022 x 10^23).
The answer is 4,328.1023formula units (not molecules).
To find the number of moles in 8.4 x 10^23 formula units of NaCl, you need to convert formula units to moles. Since 1 mole of any substance contains Avogadro's number of particles (6.022 x 10^23), you would divide the number of formula units by Avogadro's number to get the answer. So, 8.4 x 10^23 formula units of NaCl is equal to 1.4 moles of NaCl.
For this you need the atomic (molecular) mass of NaCl. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. NaCl=58.5 grams20.0 grams NaCl / (58.5 grams) =.342 moles NaCl
0,16 mg NaCl is equivalent to 2,7.10-5 mol.
The answer is 8 g NaCl.