I think you would also need the distance where the slope up to the shallow end starts.
If rectangular about 21,000 gallons if oval about 16,000 gallons
I'm guessing the 48 is inches, so it is 4' deep. The volume of the pool would then be 9x17x4 or 612ft3. 1 cubic foot is equal to 7.48 gallons. So 612x7.48 = 4577 gallons.
A 15-foot x 42-foot oval pool with an 8-foot deep end and a 3-foot shallow end will contain about 20,443 gallons of water.
10,408 gallons.
without knowing the actual lengths of the shallow and deep ends, nothing more than a very loose ballpark number is possible.
1.5x4x6x7.48 gallons/cubic foot=269.28 us gallons
Approximately 1,616 US gallons.
7,646.4 gallons are needed.
About 24 gallons.
About 18,402 gallons.
15 foot round? About 5000 gallons, if it's four feet deep. Here's a formula for round pools: distance across*distance across*depth*5.9 for rectangles: length*width*depth*7.5 or for a deep end: length*width*((shallow end depth + deep end depth)/2)*7.5
1 acre = 43560 sq.feet. 1 foot deep water over an acre is 43560 cubic feet, which is 325851.4 gallons in 1 foot deep. If it is 1 inch deep (1/12 foot) then it is 27154.3 gallons in 1 inch deep.