Multiply all the numbers to get the volume of the pool in cubic feet. Then divide by 7.5. That assumes the water is filled to a height of four feet. Some above-ground pools have 52" walls, which allow for a water height of 48", which is four feet. The dimensions stated above in the reworded question are for an oval pool, not a round one. I suspect the original question was for a round pool with an 18' diameter and a 4.5' wall. (The slash in 4 1/2 did not show up in the question.) If that is the case, then the answer is 3.14 times 81 times 4.5 divided by 7.5.

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How many gallons will fit into a 24 foot diameter x 4 foot high round swimming pool

5284.62 gallons

A round swimming pool 12 feet across by 4 feet deep will hold 452 ft3 which converts to 3,381 gallons

29,555.46 gallons.

It is 30.6 cubic feet = 190.3 Imperial gallons.

A 12-ft round pool with depth of 2 ft has a capacity of 1,692.2 gallons of water.

18,000

5300 Gal

There is NO way to calculate this without knowing how deep the pool is filled!

To calculate this the depth would also be needed

13,346 gallons per vertical foot.

10,408 gallons.

13,500 gallons

5300 Gal

It depends. How deep is the pool?

28 is the diameter of the pool and 4 is the height (depth). 1 cubic foot is approx. 7.48 gallons. A round swimming pool is a cylinder. So: pi x (28/2)2 x 4 = 2463 cubic feet, multiply by 7.48 = 18423.24 gallons

About 2,550 gallons.

7,646.4 gallons are needed.

About 18,402 gallons.

About 13,594 gallons.

About 24 gallons.

About 3,400 gallons.

About 13,594 gallons.

One foot of water in a round pool with a diameter of six feet is about 211Â½ gallons.

Use this formula: Diameter x Diameter x Average Depth x 5.9 = Total Gallons