The hose is a cylinder. The diameter is 2 inches so the radius is 1 inch. Volume = (length)(pi)(radius)2 =(15 feet)(12 inches/ft)(3.14)(1)2 = 565.2 inches3 = 565.2 cubic inches 1 US gallon = 231 cubic inches So, = 565.2 divided by 231 = 2.45 gallons of oil answer was rounded. ----
A standard fire hose is 50 feet long. A hose this length with a 2-inch radius grants about 4.36 cubic feet. This volume holds 32 gallons of water.
There need not be any water at all in the hose! The capacity of the hose is 3.41 cubic feet.
12.5
179.53 gallons
100 feet by 100 feet by one inch equates to 6,233.76 gallons of water.
6.5 gallons give or take....
100 feet of 3-inch pipe holds 36.73 gallons of water.
5.5 gallons per 15 feet of 3-inch pipe.
Roughly 1 gallon for every 18 inches of hose.
One gallon is 231 cubic inches. Assuming cyllindrical shape of hose, it contains 100 * 12 * 5 * PI * 0.25 * 52 cubin inches, which is 11780 cubic inches = 51 gallons.
You would need 2,451 feet of 2-inch pipe for 400 gallons.
61.2 gallons for every 15 feet.