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# How many gallons of water do you need to fill an 18 x 28 foot pool so the deep end is about 9 feet and the shallow end is 3 feet deep?

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###### 2005-11-21 02:12:46

without knowing the actual lengths of the shallow and deep ends, nothing more than a very loose ballpark number is possible.

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## Related Questions

For a rectangular pool and assuming the shallow end is the standard 3 feet deep, the total volume will be about 14,541 gallons of water.

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 26,660 gallons of water.

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 38,507 gallons of water.

If the pool is 8 feet at the deep end and 3 feet at the shallow end, the total volume will be 39,494 gallons of water.

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 21,722 gallons of water.

If the pool is 8 feet in the deep end and 3 feet in the shallow end, the total volume will be about 59,900 gallons of water.

You need more information. But, let's assume the pool is 8 feet deep at the deep end and 3 feet at the shallow end. If the pool is rectangular, the total volume will be 28,798 gallons of water.

if the shallow end is 4 ft and the deep end is 8 feet, you could average that to 6 feet and say, 10x15x6 = 900 cubic feet, and since 1 cubic foot of water is 7.48 gallons, that would be 6732 gallons, so it depends on how deep the pool is

A pool that is 32 feet long, 16 feet wide and with a depth from 3 feet in the shallow end to 8 feet in the deep end has a capacity of about 21,070 gallons of water.

If the pool is a constant 9 feet deep the total volume would be 48,600 gallons. However, if 9 feet is only the deep end and the shallow end is 3 feet deep, the gallons changes to 32,400 gallons.

It really depends on the depth of the shallow end. However, let's say the shallow end is three feet deep. In that case, the pool holds up to about 22,980 gallons of water.

10,710. 10,710. The calculation for a rectangle pool is: ((Shallow end depth + deep end depth) / 2) * length * width) = pool volume in cubic feet Pool cubic feet * 7.5 = gallons of water the pool holds

49,000 litres, 12945 US gallons or 10780 Imperial Gallons. See calculation and conversion charts on web link.

Assuming the slope of the bottom is uniform, then the volume is 42979 Imperial gallons, approx.

An in-ground pool that is 40 feet by 20 feet with the shallow end being 3ft deep and the deep end being 9ft deep has a volume of approximately 35,900 US gallons. (The depth of variable depth pools is generally calculated by adding the shallow and deep ends and dividing by two).

Assuming you mean the pool is 14 feet by 28 feet and has a shallow end of 4 feet and a deep end of 6 feet, then the total water volume would be approximately 14,700 gallons.

Depends on the depth. If it is 4 feet deep and it is cicular with a diameter of 24 feet then you have approx. 13,553 gallons of water. If it is 3 feet deep then you have approx. 10,152 gallons of water.

No. Tsunamis are only a few feet high in deep water. When they reach shallow water they become much higher.

If the pond is uniformly 6-feet deep it would contain about 1,955,109 gallons of water.

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