34 moles of NaCl is equivalent to 1 986,95 g.
This is 0,0584 g of NaCl.
1 teaspoon of salt (NaCL) = 6 grams of NaCL or 2,360 mg of sodium (Na). (Na molecular wt is 23, Cl is 35.5, so NaCl is 58.5, so Na is 40 % times grams of wt of NaCl.) So 1 gram NaCl X 1 tsp/6 g NaCl = 0.16667 tsp NaCl or if you want Sodium ( how salt is expressed on food labels) then 1 gram of Na X 1 tsp NaCl/2.360 gram Na = 0.42 tsp Na.
The formula mass of NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 60/58.5 = 1.03mol So there is 1.03 moles of NaCl in a 60 gram pure sample.
65% of 34m= 65% * 34= 0.65 * 34= 22.1m
34m is equivalent to 34000cm so 500cm is smaller than 34000cm
79,9 g NaCl is equivalent to 1,367 moles.The formula mass of the compound sodium chloride, NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 79.9/58.5 = 1.37molThere are 1.37 moles of sodium chloride in a 79.9 gram pure sample of the compound.
Gram percent is the number of grams of a solute per 100 grams of a solution. For example, if a solution of NaCl and water was said to have a 0.02g% of NaCl, this would mean that for 100g of saline solution, 0.02 of those grams are salt. Since 1L of water weighs 1kg (at normal conditions), there would be .2g of NaCl in 1L of a 0.02g% NaCl solution.
i have a stevens model 34m what is its value looks in excellent condition
i have stevens model 34m and know not a thing about it.Your Savage/Stevens made model 34M was made from 1969-1973.it was chambered in .22 Win Mag.(.22WMR).The Savage/Stevens model 46 is simular to the model 34M but has a Tubular magazine which was made during the same time frame(1969-1973).
Strictly, the compound NaCl does not have "moles", because the compound is ionically bonded. The gram formula unit mass, which is substituted for molar mass for ionic compounds, is 58.44, and 2.00 g of NaCl therefore contains 2.00/58.44 or 3.42 X 10-2 gram formula units.
1292 m2
For NaCl [note correct capitalization], normality is the same as molarity, the number of moles or, for ionically bonded compounds such as NaCl, gram formula masses per liter of solution, because the ions produced from NaCl in water are monovalent. The gram formula mass of NaCl is 58.44. Therefore 100 g of NaCl constitute 100/58.44 or 1.71 gram formula masses, to the justified number of significant digits. If the final volume of the solution is 1 litre, this is also the normality. If the volume is not considered exact, only one significant digit would be justified for normality, which should then be specified as 2.