The formula mass of NaCl is 23.0 + 35.5 = 58.5Amount of NaCl = 60/58.5 = 1.03mol
So there is 1.03 moles of NaCl in a 60 gram pure sample.
To find the moles of salt in the mixture, we need to first determine the mass of salt present. Since the mixture is 48% salt, the mass of salt can be calculated as 74 grams * 0.48 = 35.52 grams. Next, we convert the mass of salt to moles using the molar mass of salt (NaCl), which is approximately 58.44 g/mol. Therefore, the number of moles of salt in the mixture is 35.52 grams / 58.44 g/mol ≈ 0.61 moles.
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
First weigh the salt, preferably in grams. To finish the question let pretend it weighed 2g. Next calculate the molar mass of salt (NaCl). Na = 22.98976928 g/mol plus Cl = 35.45 g/mol so NaCl = 58.43976928 g/mol. If 58.43976928 is 1 mol, 2 g is: 2/58.43976928 = 0,034 moles.
Common salt is Sodium Chloride, NaCl salt is composed of two radicals acidic and basic radicals such as NaCl and Na2SO4 ..........
NaCl is one atom of Na and one atom of Cl. Therefore, each molecule of NaCl has 2 atoms each, combined.
A formula unit of salt, such as sodium chloride (NaCl), represents one mole of the compound. Therefore, if you have 10 moles of salt, you have 10 formula units of NaCl. In other words, for every mole of salt, there is one corresponding formula unit. Thus, 10 moles of salt correspond to 10 formula units.
roughly a mole is a unit of measurement used in chemistry to express amounts of a chemical substance, defined as an amount of a substance that contains as many elementary entities as there are atoms in the atomic weight of the substance in grams.Sodium has an atomic weight of 22.99Chlorine has and atomic weight of 35.45NaCl has a molecular weight of 58.44Therefore a mole of NaCl would weigh 58.44 grams117 grams is therefore roughly equal to 2 moles of table salt.
To find the moles of salt in the mixture, we need to first determine the mass of salt present. Since the mixture is 48% salt, the mass of salt can be calculated as 74 grams * 0.48 = 35.52 grams. Next, we convert the mass of salt to moles using the molar mass of salt (NaCl), which is approximately 58.44 g/mol. Therefore, the number of moles of salt in the mixture is 35.52 grams / 58.44 g/mol ≈ 0.61 moles.
When salt (NaCl) is split by electrolysis, one mole of sodium (Na) and one mole of chlorine (Cl2) gas are produced. The molar mass of NaCl is 58.44 g/mol, so 40.0 g of NaCl is approximately 0.68 moles. Therefore, 0.68 moles of chlorine gas are produced.
To make a two mole salt solution in two liters of water, you'll need 4 moles of salt (2 moles/L * 2 L = 4 moles). The molar mass of salt (NaCl) is approximately 58.44 g/mol, so 4 moles would be 233.76 grams (4 moles * 58.44 g/mol = 233.76 g).
Two moles of sodium chloride is equivalent to 116,88 (rounded) g.The molar mass of NaCl 58.5 grams per mole. 117 grams of salt is equivalent to two moles. Dissolve this much of salt in exactly 1L of distilled water in a volumetric flask to prepare 2M NaCl.
1.24 x 10 (18th) molecules .12mg x 1g/1000mg x 1mol/58.443g (molar mass of NaCl) x 6.022 x 10(23rd) molecules/1mol =1.236 x 10 918) molecules :) hope this helps! -forensics major currenly!!
Molarity = moles of solute/volume of solution. 1 liter = 1000 millilitetrs 3.00M = X Moles/1000ml = 3000 millimoles, or 3 moles NaCl 3 moles NaCl (58.44g NaCl/1mol NaCl ) = 175.32 grams needed. About 4/10 of a pound of salt.
NaCl is the formula unit of sodium chloride (halite, rock salt, table salt, plain salt, common salt, edible salt etc.). NaCl has 2 atoms in the formula unit.
First weigh the salt, preferably in grams. To finish the question let pretend it weighed 2g. Next calculate the molar mass of salt (NaCl). Na = 22.98976928 g/mol plus Cl = 35.45 g/mol so NaCl = 58.43976928 g/mol. If 58.43976928 is 1 mol, 2 g is: 2/58.43976928 = 0,034 moles.
0.051 molesWe know the molecular weight of NaCl is 58.443 g/mol and that the formula for the dissociation of salt in water looks like this:NaCl (aq)-->Na+ + Cl-So we can see that there is a one to one mole ratio between NaCl and sodium ions. All we have to do to find the moles of ions is3.00g * 1mol NaCl/58.443 g NaCl = 0.051 mol NaClFrom here we apply the ratio of 1 mol NaCl : 1 mol Na+ (though, since the ratio is one, it's not really necessary in this case):0.051 mol NaCl * 1 mol Na+/1mol NaCl = 0.051 mol Na+
The equivalent weight of a salt is the molecular weight of the salt divided by the number of ions produced when the salt dissolves in water. It is used to calculate the amount of salt needed in a reaction based on the amount of ions present.