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How many gram of O2 will be required to completely react with 0.3 moles of Aluminium?
Wiki User
∙ 6y ago
The Balanced reaction equation is
4Al(s) + 3O2(g) = 2Al2O3(s)
The proportions are 4:3::0.3: x
Hence
4/3 = 0.3/x
Algebraiucally rearrange
x = 0.3 X 3 / 4
x = 0.225 moles of oxygen
Hence 0.225 = mass(g) / 32
mass = 0.225 X 32 = 7.2 grames.
lenpollock
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