The reaction equation is 8 F2 + 2 NH3 equals N2F4 + 6 HF2. So every mole of NH3 requires four moles of F2. This means 14 moles of F2 or 532 grams.
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how many moles are in 95.0 gram of octane?
The answer is 0,111 moles.
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
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40 moles of LiOH
.44 moles BeCl2
how many moles are in 95.0 gram of octane?
The answer is 3 moles.
moles = mass/Mr moles = 100/(23+16+1) moles of NaOH = 2.5mol
The answer is 0,111 moles.
Balanced equation first. 2CH4O + 3O2 -> 2CO2 + 4H2O 23.5 moles methanol (3 moles O2/2 mole CH4O) = 35.3 moles oxygen needed --------------------------------------
10 moles of nitrogen dioxide are needed to react with 5,0 moles of water.
To form ammonia, reaction is N(2) + 3H(2) ---> 2NH(3) + H(2)O. As you can see for 1 mole of nitrogen three moles of hydrogen is required. Hence for your question, 1.13 moles nitrogen is required.
2C2H2 + 5O2 ---->4CO2 + 2H2O so 1 mole of acetylene (ethyne) reacts with 2.5 moles of oxygen. Answer 2.5 moles