Here is the solution,
for 1mole NH3 or ammonia,
N: 14.0067 g/mol x 1
H: 1.00794 g/mol x 3
So approximately it is--> 17.03052 g/mol)
Now multiply this into 4.5 for 4.5 moles of ammonia, --> 4.5x17.03052 =76.64g
4.65 g HF * 1mol HF * 2 mol NH3 * 17.04g NH3
------------ ----------- ----------- --------- = 1.32 g NH3
20.01g HF 6 mol HF 1 mol NH3
I mole of ammonia is 17g, so 4.5 moles are 76.5g
This mass is 76,6395 g.
3,13 g hydrogen are needed.
45/94.2 is 0.4777 moles
That is 45 teaspoons.
Any number grams with time
1.5873283 ouncesHere is the formula in case you are interested -45 g*1 oz28.34952313 g=1.587328288 oz
45 oz = 1,276 g The direct formula to convert 45 oz to grams: 45 oz* 28.34952313 g 1 oz = 1,275.728541 g
45/94.2 is 0.4777 moles
45 grams, since the atomic mass of water is 18g.18 * 2.5 = 45
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
There's a thousand grams in a kilogram, 45 grams is 0.045 kilograms.
450 grams
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
1kg = 1000g. Therefore, 45 x 1000 = 45000 grams.
6.25 kg/45 litres = 6250 grams/45 litres = 6250/45 grams per litre =138.88... gpl
2
That is 45 teaspoons.
There are 1000 milligrams in grams. Therefore, 45 grams is equal to 45 x 1000 = 45000 milligrams.
45