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5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
120 grams of calcium contain 2,994 moles.
735 g of Ca3(PO4)2 are obtained.
7,68 grams of calcium nitride is equal to 0,052 moles.
0,27 moles of calcium contain 10,82 g calcium.
42,5 grams calcium is equivalent to 1,06 moles.
5000 grams calcium (1 mole Ca/40.08 grams) = 124.75 moles Calcium
Balanced equation first. Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 +2H3PO4 1.523 moles H2SO4 (1 mole Ca3(PO4)2/3 moles H2SO4)(310.18 grams/1 mole Ca3(PO4)2) = 157.5 grams of Calcium phosphate
120 grams of calcium contain 2,994 moles.
735 g of Ca3(PO4)2 are obtained.
126 grams calcium (1 mole Ca/40.08 grams) = 3.14 moles of calcium ------------------------------
7,68 grams of calcium nitride is equal to 0,052 moles.
0,27 moles of calcium contain 10,82 g calcium.
3 moles of calcium is equivalent to 120,234 g.
28 grams calcium oxide (1 mole CaO/56.08 grams) = 0.50 moles CaO =============
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3.8 grams calcium (1 mole Ca/40.08 grams) = 0.09 moles calcium ==============