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Balanced equation first.

Ca3(PO4)2 + 3H2SO4 -> 3CaSO4 +2H3PO4

1.523 moles H2SO4 (1 mole Ca3(PO4)2/3 moles H2SO4)(310.18 grams/1 mole Ca3(PO4)2)

= 157.5 grams of Calcium phosphate

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Q: What mass of calcium phosphate can be completely reacted with 1.523 moles of sulfuric acid?
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