HPO4 does not exist. HPO42- would be the dibasic form of phosphoric acid and be the hydrogen phosphate ion. H3PO4 also exists and is phophoric acid. So if two moles of NaOH were reacted with phosphoric acid 2Na+ HPO42- would be formed disodium hydrogen phosphate.
MONO HYDROGEN phosphate is written as HPO42-.
Phosphoric Acid would be the more common name. Hydrogen Phosphate works as well.
Hydrogen Phosphate
You see it's called Hydrogen Phosphate because of the Hydrogen(H) and the Phosphate(PO4). I like chocolate.
HPO4 is hydrogen phosphate.
Calcium Hydrogen Phosphate.
Mono hydrogen phosphate
monohydrogen phosphate
hpo42
PO43-
There are three protolysis steps:H3PO4 ---> H+ + H2PO4-H2PO4- ---> H+ + HPO42-HPO42- ---> H+ + PO43-
PO43-
monohydrogen phosphate
hpo42
Formula: HPO42-
PO43-
There are three protolysis steps:H3PO4 ---> H+ + H2PO4-H2PO4- ---> H+ + HPO42-HPO42- ---> H+ + PO43-
PO43-
PO43- (phosphate) is the conjugate base of HPO42- (monohydrogen phosphate)
NaH2PO4(aq) + H2OàH3PO4(aq) + NaOH(aq) H3PO4(aq)ßàH+(aq) + H2PO4_(aq) H2PO4-(aq)ßàH+(aq) + HPO42-(aq) HPO42-(aq)ßàH+(aq) + PO43-(aq)
A polyprotic acid can (in a multi-step reaction) donate more than one proton per molecule of acid.E.g. phosphoric acid can do 'the trick' three times:H3PO4 --> H+ + H2PO4-H2PO4- --> H+ + HPO42-HPO42- --> H+ + PO43-
HPO42- is the most abundant phosphate present at pH=7.5, but H2PO42- is also there in (less) significant amounts. PO43- and H3PO4 are practically absent at pH 7.5.This is because it is between the valuespH=pKa,3= 12.4 (at which value there is 50% HPO42- and 50% PO43-) andpH=pKa,2= 7.2 (at which value there is 50% HPO42- + 50% H2PO42-)[Cf. Related links: A graph of "The phosphate presency"]
H= +1 P= +5 O= -2 Source: Mastering Chemistry
Yes, mono- and di-dissociation may occur, finally resulting (at high pH levels) in PO43- and 2H+.H2PO4- --> H+ + HPO42- eventually followed by the second step (at higher pH levels):HPO42- + OH- --> PO43- + H2OIt is ALSO a monoprotic base by accepting a proton:H2PO4- + H+ --> H3PO4