1 mole H2O = 18.02g
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water is H2O ... 2 x 1.008 + 1 x 15.996 = 18.012 g/mole = 18.01 grams
The molar mass of water is approximately 18.02 g/mol. Therefore, one mole of water would weigh approximately 18.02 grams, considering 4 significant figures.
To calculate the grams of propane needed to produce 8.00 grams of water, you start by converting the mass of water to moles using the molar mass of water. Then, you use the balanced chemical equation for the combustion of propane to determine the mole ratio between propane and water. Finally, convert the moles of water to moles of propane using the mole ratio and then to grams of propane using the molar mass of propane.
First you find the Molar Mass of water using the values on the periodic table.2 Hydrogen + 1 Oxygen2*1.01 + 16.00 = 18.02 g/molThen using factor-label to cancel out units(100g H2O)*(1 mol H2O / 18.02 g H2O) = 5.54938957 molSo the number of moles in 100g of H2O is about 5.55 moles.Hope that helps.
The balanced chemical equation for the formation of water is 2H2 + O2 -> 2H2O. This means that 2 moles of hydrogen react with 1 mole of oxygen to form 2 moles of water. Using the given masses, convert them to moles and determine the limiting reactant. Finally, calculate the mass of water produced from the limiting reactant.
The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.
First, convert the mass of fructose to moles using its molar mass. Then, calculate the moles of water using its molar mass. Finally, divide the moles of fructose by the volume of the solution (in liters) to determine the molarity.
5 grams water is 1 teaspoon
The most accurate answer is 0.2 mol/kg.Related Information:The number of significant figures in the final answer must be based on the given with the least number of significant figures which is 2L.
The answer depends on whether you are measuring the drops from a slow drip or the number of drops of water in an ocean!
The rule for significant figures is that all non-zero digits are considered significant. Zeros between non-zero digits are significant, as well as trailing zeros after a decimal point. Leading zeros (zeros to the left of the first non-zero digit) are not considered significant.
To calculate the grams of propane needed to produce 8.00 grams of water, you start by converting the mass of water to moles using the molar mass of water. Then, you use the balanced chemical equation for the combustion of propane to determine the mole ratio between propane and water. Finally, convert the moles of water to moles of propane using the mole ratio and then to grams of propane using the molar mass of propane.
Pure water can roughly hold 0.073 grams per cm at 20 degree Celsius.Impurities can change the figures.
2.000 = 2,000.000g 6.5 determines only one significant figure 2,000 + 6.5 + 47.546 = 2,054.046 which would be 2,054.0 In scientific notation that would equal 2.0540 * 103
First you find the Molar Mass of water using the values on the periodic table.2 Hydrogen + 1 Oxygen2*1.01 + 16.00 = 18.02 g/molThen using factor-label to cancel out units(100g H2O)*(1 mol H2O / 18.02 g H2O) = 5.54938957 molSo the number of moles in 100g of H2O is about 5.55 moles.Hope that helps.
76231865367 water
To convert 1.5 mol of water into grams, you can use the molar mass of water, which is approximately 18.015 g/mol. Multiply 1.5 mol by the molar mass to get the grams of water. Therefore, 1.5 mol of water is equal to 27.02 grams.
To find the mass of water containing 5.0 grams of hydrogen, we need to set up a proportion using the mass percentage of hydrogen in water. Since water is 11.2% hydrogen by mass, we can calculate the mass of water using the formula: (5.0 grams of hydrogen) / (11.2 grams of hydrogen per 100 grams of water) = x grams of water. Converting grams to kilograms, the mass of water containing 5.0 grams of hydrogen would be 5.0 g / 11.2% = 44.64 g. This figure converted to kilograms is 0.04464 kg.
The balanced chemical equation for the formation of water is 2H2 + O2 -> 2H2O. This means that 2 moles of hydrogen react with 1 mole of oxygen to form 2 moles of water. Using the given masses, convert them to moles and determine the limiting reactant. Finally, calculate the mass of water produced from the limiting reactant.