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How many grams of propane react to produce 8.00 grams of water?
Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1
How many moles of water are there in 100 grams of water?
First you find the Molar Mass of water using the values on the periodic table.2 Hydrogen + 1 Oxygen2*1.01 + 16.00 = 18.02 g/molThen using factor-label to cancel out units(100g H2O)*(1 mol H2O / 18.02 g H2O) = 5.54938957 molSo the number of moles in 100g of H2O is about 5.55 moles.Hope that helps.
How many grams of water can be produced from 50 grams of hydrogen and 300 grams of oxygen?
2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2300 grams O2 x 1 mole O2/32 g = 9.375 moles O2Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 molesgrams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)
How many joules of heat are needed to completely vaporize 24.40 grams of water at its boiling point?
The heat of vaporization of water is 40.79 kJ/mol. First, determine the number of moles in 24.40 grams of water. Then, convert moles to joules using the molar heat of vaporization. This will give you the amount of heat needed to vaporize 24.40 grams of water.
What is the molarity of a solution of 12.9 grams of fructose in 31.0 grams of water?
First, convert the mass of fructose to moles using its molar mass. Then, calculate the moles of water using its molar mass. Finally, divide the moles of fructose by the volume of the solution (in liters) to determine the molarity.
What is the total mass in grams expressed in scientific notation with the correct number of significant figures of a solution containing 2.000 kg of water 6.5 g of sodium chloride and 47.546 g of?
2.000 = 2,000.000g 6.5 determines only one significant figure 2,000 + 6.5 + 47.546 = 2,054.046 which would be 2,054.0 In scientific notation that would equal 2.0540 * 103
How can you measure 15 grams using spoons?
5 grams water is 1 teaspoon
How do you encorportate significant figures when measuring the number of drops of water?
The answer depends on whether you are measuring the drops from a slow drip or the number of drops of water in an ocean!
How much weight can the surface tension of water hold?
Pure water can roughly hold 0.073 grams per cm at 20 degree Celsius.Impurities can change the figures.
How many grams of propane react to produce 8.00 grams of water?
Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1
What is the rule about significant figures?
1. All non-zero numbers are significant 2. Zeros between non-zero digits count 3. Zeros at the beginning of a number do not count 4. Zeros at the end of a number that does not have a decimal are not significant 5. Zeros at the end of a number with a decimal are significant
Water its 11.2 percent by mass hydrogen How many kilograms of water would contain 5.0 grams of hydrogen?
To find the mass of water containing 5.0 grams of hydrogen, we need to set up a proportion using the mass percentage of hydrogen in water. Since water is 11.2% hydrogen by mass, we can calculate the mass of water using the formula: (5.0 grams of hydrogen) / (11.2 grams of hydrogen per 100 grams of water) = x grams of water. Converting grams to kilograms, the mass of water containing 5.0 grams of hydrogen would be 5.0 g / 11.2% = 44.64 g. This figure converted to kilograms is 0.04464 kg.
How many moles of water are there in 100 grams of water?
First you find the Molar Mass of water using the values on the periodic table.2 Hydrogen + 1 Oxygen2*1.01 + 16.00 = 18.02 g/molThen using factor-label to cancel out units(100g H2O)*(1 mol H2O / 18.02 g H2O) = 5.54938957 molSo the number of moles in 100g of H2O is about 5.55 moles.Hope that helps.
How to convert 1.5 mol of water into grams?
First find the molar mass of water using the atomic mass of the elements that make up water (H2O) = (2x1.01g/mol+16g/mol) = 18.02 g/mol. Then we know 1mol water is 18.02g so we multiply 18.02g/mol H20 x 1.5mol H2O to get 27.03g but rounds to 27 because 1.5mols has two significant digits.
How many grams of water can be produced from 50 grams of hydrogen and 300 grams of oxygen?
2H2 + O2 ===> 2H2O50 grams H2 x 1 mole H2/2 g = 25 moles H2300 grams O2 x 1 mole O2/32 g = 9.375 moles O2Limiting reactant is O2, so maximum moles of H2O formed = 9.375 O2 x 2H2O/1 O2 = 18.75 molesgrams H2O = 18.75 moles H2O x 18 g/mole = 337.5 g H2O = 340 g (to 2 significant figures)
What percentage is 150 grams per 10000 gallon s of water?
To calculate the percentage of 150 grams in 10000 gallons of water, we first convert the gallons to grams using the density of water (1 gallon = 3785.41 grams). Then we divide the weight of the substance (150 grams) by the total weight of water (10000 gallons converted to grams). Finally, we multiply by 100 to get the percentage: (150 grams / (10000 gallons * 3785.41 grams)) * 100 = 0.395%.
How much heat is required to warm 1.60 L of water from 22.0 ∘C to 100.0 ∘C (Assume a density of 1.0g/mL for the water.) Express your answer in joules to two significant figures?
76231865367 water
