4 gram molecular weights (moles): However many grams four moles* of the solute is.
* Hint: four moles of sodium chloride weighs less than four moles of sucrose.
You need 50 g of this drug.
You need 0,9 glucose.
A 0.5N Na2CO3 used in determining the concentration of an unknown HCl solution has a weight of 1.06 grams. To find the weight, you need to first find out how many moles there are by calculating molarity times volume.
You prepare a solution by dissolving a known mass of solute into a specific amount of solvent. In solutions, M is the molarity, or moles of solute per liter of solution. For 300 ml of a 0.1 M Na CL solution from a solid Na CL solution and water you need water and sodium chloride.
We need 14,8 g oxygen.
4314.9 grams
If this is .020m solution, you need 3.81g If this is .20m solution, you need 38.1g If this is 20m solution, you need 3810g
You need 50 g of this drug.
We need 1,27 g iodine.
You need 116,88 g dried and pure sodium chloride.
Need to know how much of the solution you have.
14.575 round is 14.6 g
The atomic weight of Na-OH is 23+16+1= 40. So to prepare the one N solution of Na-OH, you need to add 40 grams of Na-OH in one litre of water. To prepare the 4N Na-OH solution, you need to add 160 grams of Na-OH in one litre of water.
599.6
To make a 10% sugar solution you need to dissolve 10 grams of sugar and bring the volume up to 100 ml
In this instance, 50 mol of sodium chloride is needed and molar mass of NaCl is 58.5 g/mol. Hence the mass we need is 29250 g. But this amount of salt could not be dissolved in 500 ml of water, so we cannot prepare this solution practically.
0.5 = moles calcium nitrate / 3 L 0.1667 moles Ca(NO3)2 0.1667 * 148 = 24.7g Ca(NO3)2