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Answered 2010-08-04 21:14:47

Molarity = moles of solute/Liters of solution

3 M KBr = moles KBr/1 liter

= 3 moles KBr (119 grams/1 mole KBr)

= 357 grams needed

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HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.


Let me translate the question: I think you are asking how to make a 0.1 molar solution of Na2S2O4. Molarity is moles of solute divided by liters of solution. To make this easy, let's assume you want to make one liter of the solution. That means you need to dissolve in 0.1 moles of Na2S2O4 into one liter of water to make a 0.1 molar solution. The formula weight of Na2S2O4 is 174.1 grams per mole so 0.1 moles of it is 17.41 grams. Therefore you would need to dissolve 17.41 grams of Na2S2O4 into one liter of water to make a 0.1 molar solution.


how many grams of calcium nitrate are needed to make a 500ml volume of a .5 molar solution


A 1 molar solution by definition is 1 mole of something, in this case glucose, in 1 liter of solution. The molecular weight of something can be found on the perdiodic table. The weight listed on the periodic table is the grams in a mole, these of course are for atoms. 12 H + 6 C +6O + 188.1558 grams in a mole of glucose. Put this weight into one liter of water.


What volume do you want to make. To make 1 liter, you take the 185 g (the molar mass) and dissolve in enough solvent to make the final volume 1 liter.


Dissolve 2.92 grams edta in one liter distilled water. The molar mass of edta is 292.24 g mol-1. Molarity is moles of solute divided by liters of solute. To make a 0.01m solution, take 0.01*the molar mass of the substance and dissolve it in one liter of water. So: 0.01*292.24=2.92 grams.


In addition to the molar concentration, you need to know the volume of solution desired and the molar mass (gram/mole) of the substance. Then, molar concentration = mole/liter and with the known volume, you calculate as follows:mole/liter x liter x gram/mole = grams. Measure out the calculated grams and dissolve in enough solvent to make the final volume.


10 percent acetic acid indicates there is .1 liters of acetic acid, which is equal to 1.75 moles, or 105 grams per liter. To make this solution, add 7 liters of the 2M solution to 1 liter of water, or 7/8 solution to 1/8 water.



In a 3.4 M solution, there are 3.4 moles per liter. If you want to make 3 liters of solution, you'll need 3 liter * 3.4 moles/liter = 10.2 moles The molar mass of KCl is 39.098 g/mole K + 35.453 g/mole Cl = 74.551 g/mole KCl To get the number of grams, multiply the number of moles by the molar mass: 10.2 moles * 74.551 g/mole KCl = 760.4202 g = 0.760 kg


A 0.205 M solution will have 0.205 moles per liter. 250 milliliters is 1/4 of a liter, so in that sample, there will be 0.05125 moles. NaOH has a molar mass of 39.9971 grams per mole, so 2.05 grams added to 250 mL of water will make the desired solution.


(158 g = 1 mole) --- molar mass of potassium permanganate. You also need to specify the volume to be made. For 1 liter just add 15.8 g in a volumetric flask to make 1000 ml (1 liter) of solution.



Take twice its molar mass in grams and then dissolve in water up to 1.000 Litre


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I think you are misreading I for 1. it is one molar concentration of NaOH, or sodium Hydroxide. To make mix 40 grams with enough water to make a liter.


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How do you make and calculate solution khp 2000 ppm.


1 molar means 1 mole / liter. Since you want to make 1 liter, you will need 1 mole of NaOH. Look at the periodic table: Na is 23 g/mol, O is 16 g/mol, and H is 1 g/mol. Add these up and you get 40 grams per mole of NaOH. Since you need 1 mole, then 40 gramswill make one mole.


The molecular weight of NaCl is 58.44; sodium =22.99; Chlorine=35.45. A 1 molar solution is the molecular weight in grams in 1 litre of water, so a 3.5 molar solution would be 58.44g multiplied by 3.5, which is 204.54g in 1L.


Dissolve 111 g anhydrous CaCl2 in 1 L distilled water.


4 g NaOH is dissolved with water to make a 1 liter solution, or any proportional amounts of each. -- half of each, 2 g NaOH and dissolve to make 500 ml solution.


5 millimolar (5 thousandths of a mole per liter) is equal to 5000 micromolar ( 5000 millionths of a mole per liter). To make a 50 micromolar solution from 5 millimolar stock solution, you therefore need 5000/50 = 100 fold dilution. Remove a 10 ml aliquot of stock and transfer to a 1000ml (1 liter) volumetric flask. Dilute with the solvent -usually water, and fill up to the graduation mark. You will now have 1 liter (1000 ml) of 50 micromolar solution.


Molarity=[w/GMW]*[1000/volume(in mL)] 0.5=[w/342]*[1000/100]=17.1g similarly,34.2g sucrose is to dissolved in water and made up to 100mL to make 1molar solution and 171g to make 5molar solution.



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