First write a balanced chemical equation: 2K + Br2 ---> 2KBR Find the limiting reactant by using the moles of each element and determining which one gives you the smallest number of moles of potassium bromide. 2.92 mol K (2 mol KBr/2 mol K)= 2.92 mol KBr 1.78 mol Br2 (2 mol KBR/1 mol Br2)=3.56 mol KBr potassium is your limiting reactant so the max. number of moles of KBr that can be produced is 2.92 mol of KBr
How many moles of potassium bromide can be produced from the reaction of 2.92 moles of potassium with 1.78 moles of bromine gas?
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
This is a halogen single replacement reaction, in which the more active chlorine will take the place of the bromine in the potassium bromide. 2KBr + Cl2 --> 2KCl + Br2
Potassium and bromine form the ionic compound potassium bromide with the chemical formula KBr.
Potassium Bromide : KBr
Yes: KBr--------K+ + Br- Br- is the anion.
Bromine and Potassium iodide react to form Potassium bromide and Iodine.
A salt named potassium bromide.
Potassium and bromine form the ionic compound potassium bromide with the chemical formula KBr.
This is a halogen single replacement reaction, in which the more active chlorine will take the place of the bromine in the potassium bromide. 2KBr + Cl2 --> 2KCl + Br2
Potassium and bromine form the ionic compound potassium bromide with the chemical formula KBr.
Potassium bromide (KBr) is a white solid formed by the reaction of potassium hydroxide and bromine.
Potassium bromide.
The ionic compound potassium bromide, with formula KBr.
The reaction of chlorine with potassium bromide is a reduction-oxidation reaction. The chloride oxidizes bromide ions to molecular bromine, and itself is reduced to chloride ions.
Potassium bromide is a White solid
you will get potassium bromide
chlorine plus potassium bromide gives bromine plus potassium chloride. Here is the symbol equation, but remember that the numbers AFTER the symbols should be subscripts. Cl2 + 2KBr = Br2 + 2KCl