1.21g
Glycine intracts with one mole of Bezoyl chloride in the presence of 10% (w/v) solution to yield hippuric acid with the elimination of one mole of hydrochloric acid. The excess of 10% NaOH solution serves two purposes, first; to remove unreacted benzoyl chloride. The NaOH solution hydrolyses the excess of benzoyl chloride present in reaction mixture, thereby resulting in formation of sodium chloride and sodium benzoate, which being water soluble remains in solution. Secondly the hydrochloric acid eliminated reacts with NaOH to yield NaCl. Both sodium benzoate and sodium chloride are water soluble, whereas the desired product hippuric acid being insoluble may be separated easily.
You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).
The molar mass of silver chloride (AgCl) is approximately 143.32 g/mol. Since a formula unit represents one molecule of the compound, the mass in grams of a single formula unit of silver chloride is 143.32 grams.
Converting between moles of aluminum chloride and grams of aluminum chloride is most similar to converting between eggs and dozens of eggs. Just like one dozen equals 12 eggs, one mole of aluminum chloride contains Avogadro's number of particles (6.022 x 10^23) which corresponds to its molar mass in grams.
There are two chloride ions in one formula unit of barium chloride.
Silver chloride - AgClAg (107.89 grams) + Cl (35.45 grams) = 143.34 grams
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
Glycine intracts with one mole of Bezoyl chloride in the presence of 10% (w/v) solution to yield hippuric acid with the elimination of one mole of hydrochloric acid. The excess of 10% NaOH solution serves two purposes, first; to remove unreacted benzoyl chloride. The NaOH solution hydrolyses the excess of benzoyl chloride present in reaction mixture, thereby resulting in formation of sodium chloride and sodium benzoate, which being water soluble remains in solution. Secondly the hydrochloric acid eliminated reacts with NaOH to yield NaCl. Both sodium benzoate and sodium chloride are water soluble, whereas the desired product hippuric acid being insoluble may be separated easily.
You get salt at the bottom of the pan!
You would need 35.5 grams of chlorine to combine with 23 grams of sodium to make 58.5 grams of sodium chloride. This is based on the molar mass of sodium chloride, where one mole of sodium chloride is composed of one mole of sodium (23 grams) and one mole of chlorine (35.5 grams).
Well, honey, strontium chloride has a molar mass of about 158.53 grams per mole. So, if you're looking for the amount of grams in a specific quantity of strontium chloride, you'll need to do a little math based on the number of moles you have. But hey, don't stress too much, just grab a calculator and you'll have your answer in no time.
The molar mass of silver chloride (AgCl) is approximately 143.32 g/mol. Since a formula unit represents one molecule of the compound, the mass in grams of a single formula unit of silver chloride is 143.32 grams.
Converting between moles of aluminum chloride and grams of aluminum chloride is most similar to converting between eggs and dozens of eggs. Just like one dozen equals 12 eggs, one mole of aluminum chloride contains Avogadro's number of particles (6.022 x 10^23) which corresponds to its molar mass in grams.
There are two chloride ions in one formula unit of barium chloride.
The gram atomic mass of calcium is 40.08, the formula of anhydrous calcium chloride is CaCl2, showing that each formula unit contains one calcium atom, and the gram formula mass of anhydrous calcium chloride is 110.99. Therefore, 19050.9 grams of calcium chloride contains 19050.9(40.08/110.99) or 6.880 X 103 grams, to the justified* number of significant digits. ____________________________________________ *There may well be tables of gram atomic and gram formula masses more modern than the one I am using that would allow for more significant digits in the answer.
Silver chloride is AgCl, that is one Ag+ and one Cl- , ionically bound together.
For this problem, the atomic mass is required. Take the mass in grams and divide it by the atomic mass. Then multiply it by Avogadro's constant, 6.02 × 1023. AlCl3= 133.5 grams10.5 grams Cu / (133.5 grams) × (6.02 × 1023 atoms) = 4.73 × 1022 atoms