64 moles of chlorine atoms would be 64 x 35.5 grams, i.e. 2272 grams. If you meant the substance chlorine, which consists of Cl2 molecules, it would be 4544 grams.
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
I assume that is 28.0 grams.28.0 grams MgCl2 (1 mole MgCl2/95.21 grams)= 0.294 moles magnesium chloride==========================Now,One mole Mg 2+ = 0.294 moles Mg 2+ ions=============================2 moles Cl - = 0.588 moles Cl - ions=========================
There are 2 moles of Cl in 1 mole of CaCl2. The molar mass of Cl is 35.45 g/mol. So, in 435 g of CaCl2, there would be 2 moles of Cl, which is equal to 70.9 g of Cl.
To determine how many grams of chlorine gas (Cl₂) are produced from the decomposition of sodium chloride (NaCl), we start with the balanced chemical equation for the reaction: 2 NaCl → 2 Na + Cl₂. From the molar mass of NaCl (approximately 58.44 g/mol), 7.5 grams of NaCl corresponds to about 0.128 moles. According to the stoichiometry of the reaction, 2 moles of NaCl produce 1 mole of Cl₂, so 0.128 moles of NaCl would yield 0.064 moles of Cl₂. The molar mass of Cl₂ is approximately 70.90 g/mol, resulting in about 4.54 grams of Cl₂ being produced.
In 1 mol of NaCl there is 58.44 grams. ( 22.99 grams of Na + 35.45 grams of Cl). Using stoichiometry, you cancel the grams by taking 29.22 grams/58.44 grams. So 0.50 moles of NaCl
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
0,5 moles Cl-
0.560 moles × 35.453 grams/mole = 19.85 grams
it wouldn't be moles of Cl it would be Cl2 as chlorine doesn't exist as an atom it exsists as two joined to form a compound this is very easy stuff the answer is 15 moles of Cl2 as there 30 moles of Cl hope this helps learn your moles it's easy stuff
1 mole Cl = 35.453g Cl 28.4g Cl x 1mol Cl/35.453g Cl = 0.801 mole Cl
Mg2+ + 2 Cl- are in 1 : 2 ratio (of ions) so also 0.25 : 0.50 mole ratio
2 moles of NaCl, of course. Cl would definitely limit in this one to one reaction and you would have 19998 moles Na in excess.
The molecular weight of sodium (Na) is 22.99 grams. The molecular weight of chlorine (Cl) is 35.45 grams. Therefore, there are 58.44 grams in 1 mole of NaCl. So, in 3.25 moles of NaCl, there are 58.44 gr x 3.25 = 189.93 grams.
1.409 moles chlorine (35.45 grams/1 mole Cl) = 49.95 grams of chlorine ==================