To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
A 5 gram tablet contains 5 grams.
Assuming that the water is produced by complete combustion of propane, the balanced equation is: C3H8 + 5 O2 = 3 CO2 + 4 H2O. The gram molecular mass of propane is three times the gram atomic mass of carbon plus eight times the gram atomic mass of hydrogen = 3(12.011) + 8(1.008) = 44.097, and the gram molecular mass of water is the gram atomic mass of oxygen plus twice the gram atomic mass of hydrogen = 15.999 + 2(1.008) = 18.015. The balanced reaction equation shows that four molecules of water are produced for each molecule of propane, so that the ratio of grams of propane reacted to grams of water produced is 44.097/(4 X 18.015) = 0.61191, to the justified number of significant digits. Therefore, the amount of propane required to produce 8.00 grams of water = 8.00(0.61191) = 4.90 grams to the clearly justified number of significant digits, matching the three significant digits given for 8.00, or 4.895 grams, where the last digit is depressed because it may well not be accurate within + 1
Grams is a unit of weight. One gram of anything is one gram.
There are approximately 453.592 grams in 1 pound of mineral.
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
To convert 2 lb mol of C3H8 to grams, you need to first determine the molar mass of C3H8 (propane) which is approximately 44.1 g/mol. Then, you can multiply the number of moles (2 lb mol) by the molar mass to get the mass in grams. So, 2 lb mol of C3H8 is equal to 2 lb mol * 44.1 g/mol = 88.2 g.
The plural of gram is grams.
1 hector gram = 100 grams
There are 1 gram in 1 gram. Each gram is equivalent to 1 unit of weight.
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If 3 grams of magnesium are used to form 4 grams of magnesium oxide, then 1 gram of oxygen is used in the reaction. This means 1 gram of oxygen remains unused.
A 5 gram tablet contains 5 grams.
To determine how many 0.25 grams of mercury (Hg) are in a gram, you can divide 1 gram by 0.25 grams. This calculation shows that there are 4 portions of 0.25 grams in 1 gram. Therefore, there are 4 units of 0.25 grams of mercury in a gram.
Gram
The combustion of hexane (C6H14) produces carbon dioxide (CO2) according to the reaction: C6H14 + 7O2 → 6CO2 + 7H2O. For every 1 gram of hexane burned, approximately 3.03 grams of carbon dioxide are produced. Therefore, from the combustion of B grams of hexane, the amount of carbon dioxide produced would be approximately 3.03B grams.
0.001 gram. There are 1000mg in a gram