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How many grams of K HP are needed to neutralize 18.64 ml of a 0.1004 M Na OH solution?
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Answered 2012-11-18 10:52:12
Molarity = mols of solute/L of solution
.1004 = mols of NaOH/.01864
moles of NaOH = .00187
Moles of NaOH = Moles of KHP
Now, multiply .00187 by the molar mass of KHP
.00187*204.22 = .38 g KHP
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