Molarity = mols of solute/L of solution
.1004 = mols of NaOH/.01864
moles of NaOH = .00187
Moles of NaOH = Moles of KHP
Now, multiply .00187 by the molar mass of KHP
.00187*204.22 = .38 g KHP
This is not a possible compound. Please state the chemical name of this Potassium-Hydrogen salt of 'WHAT" accurately.
97.8 - 98.2 98 worked for me
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
1.47g
93,31 g MgCl2 are needed.
How many grams of KHP are needed to exactly neutralize 36.7 mL of a 0.328 M barium hydroxidesolution
98g
262 - 266
262 - 266
97.8 - 98.2 98 worked for me
7.5 grams are needed because each milliliter is 1.50 grams, to get 5.00 mls, the calculation would be 5x1.50=7.5.
HCl has a molar mass of 36.461 grams per mole. This means that 72.922 grams of HCl are needed per liter of water to make a solution that has a concentration of 2M.
Calculate the mass (in grams) of sodium sulfide that is needed to make 360ml of a 0.50 mol/L solution
0.50 grams of BeCl2
The answer is 7,5g.
1.47g
93,31 g MgCl2 are needed.