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How many pounds are found in 25.29 grams of NaCl?
A pound (weight) is equivalent to 453.59 grams. Therefore, 25.29 grams is the same as 0.056 pounds.
How many moles in 25 grams of NaCl?
To calculate the number of moles in 25 grams of NaCl, divide the given mass by the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. Therefore, 25 grams of NaCl is equivalent to approximately 0.43 moles.
How many moles are in 240 grams of NaCl?
To determine the number of moles in 240 grams of NaCl, divide the given mass by the molar mass of NaCl. The molar mass of NaCl is approximately 58.44 g/mol. So, 240 grams of NaCl is equivalent to 240/58.44 = 4.11 moles.
How many grams of NaCl are in 225 grams of an 18 percent NaCl solution?
The answer is 8 g NaCl.
How many grams of NaCl are in 11.1 moles of NaCl?
The answer is 648,68 g.
How many moles of NaCl are in 56.0 grams of NaCl?
The answer is 0,96 moles.
How many grams of chlorine gas are needed to make 117 grams of sodium chloride?
117 grams of sodium chloride (NaCl) is equivalent to 117 grams of chlorine gas because each molecule of NaCl contains one sodium atom and one chlorine atom.
How many grams are in NaCl with 2.34 moles of Cl2?
To find the grams of NaCl with 2.34 moles of Cl2, you need to consider the molar ratio. For every 1 mole of Cl2, there are 2 moles of Cl in NaCl. So, 2.34 moles of Cl2 would be equivalent to 4.68 moles of Cl in NaCl. Using the molar mass of NaCl (58.44 g/mol), you can calculate that 4.68 moles of NaCl would be approximately 273.64 grams.
How many kilograms of NaCl are there in 540 grams of NaCl?
540 g NaCl is equal to 0,54 kg.
How many grams are in 0.48 moles if NaCl?
1 mole NaCl = 58.44g NaCl0.48mol NaCl x 58.44g NaCl/1mol NaCl = 28g NaCl
How many grams are in two moles of NaCl?
The molar mass of NaCl is approximately 58.44 g/mol. Therefore, two moles of NaCl would be 2 * 58.44 = 116.88 grams.
How many grams of NaCL are produced when 80.0 grams of O2 are produced?
It depends on the chemical reaction that is occurring. Can you provide the balanced equation for the reaction so we can calculate the amount of NaCl produced?
