The gram Atomic Mass of titanium is 47.867. Therefore, in a 0.65 mole sample, there will be 0.65 X 47.867) = 31 grams, to the justified number of significant digits.
341 grams scandium (1 mole Sc/44.96 grams)(6.022 X 1023/1 mole Sc) = 4.57 X 1024 atoms of scandium =====================
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
Na2SO4 10.0 grams Na2SO4 (1 mole Na2SO4/142.05 grams)(2 mole Na/1 mole Na2SO4)(22.99 grams/1 mole Na) = 3.24 grams of sodium -------------------------------
The gram atomic mass of germanium is 72.6, to two significant digits. Therefore, in a 3.11 mole sample there will be (3.11)(72.6) = 226 grams, to the justified number of significant digits.
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100 grams oxygen (1 mole O/16 grams)(2 mole Fe/3 mole O) = 4.17 moles iron --------------------------
# of moles = grams of substance / molar mass of substance molar mass of Barium =137.33 grams/mole #moles of Barium = 22.3 grams/ 137.33 grams/mole = 0.162382582 moles
341 grams scandium (1 mole Sc/44.96 grams)(6.022 X 1023/1 mole Sc) = 4.57 X 1024 atoms of scandium =====================
3.00 grams NaHCO3 (1 mole/84.008 grams) = 0.0357 moles of sodium bicarbonate
1.88 X 1024 molecules SO3 (1 mole SO3/6.022 X 1023)(80.07 grams/1 mole SO3) = 250 grams sulfur trioxide ===================
86.0 grams Sn (1 mole Sn/118.7 grams)(6.022 X 1023/1 mole Sn)= 4.36 X 1023 atoms of tin=================
4.003 grams
The molar mass of an element corresponds to the atomic mass of the element (found on the periodic table). The atomic mass of Sodium-Na is 22.990 g, which is also the molar mass of Na. So for 1 mole of Na, there are 22.990 grams of Na. If we had 3 moles of Na, then we would simply multiply the molar mass by 3.
35.0 moles nitrogen (1 mole N/14.01 grams) = 2.50 moles nitrogen ----------------------------
145 grams NaCl (1 mole NaCl/58.44 grams)(1 mole Na +/1 mole NaCl)(6.022 X 1023/1 mole Na +) = 1.49 X 1024 ions of sodium =====================