A 2-liter bottle of Sprite contains about 5.3 grams of carbon dioxide.
Sprite contains no carbon dioxide. It is a sparkling beverage that has carbonation added to it during the bottling process to create the fizziness that many people enjoy.
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
When 15 liters of propane are completely burned, it produces 110 grams of carbon dioxide.
A 2-liter bottle of Sprite contains about 5.3 grams of carbon dioxide.
Sprite contains no carbon dioxide. It is a sparkling beverage that has carbonation added to it during the bottling process to create the fizziness that many people enjoy.
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
If all the carbon (3 grams) reacts with the oxygen (8 grams) to form carbon dioxide, the total mass of the carbon dioxide produced will be equal to the sum of the masses of carbon and oxygen consumed. Therefore, the total mass of carbon dioxide produced would be 3 grams (from carbon) + 8 grams (from oxygen) = 11 grams.
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
When 15 liters of propane are completely burned, it produces 110 grams of carbon dioxide.
To find the moles of carbon, first calculate the moles of carbon dioxide using its molar mass. Then, from the moles of carbon dioxide, determine the moles of carbon as there is one carbon atom in each molecule of carbon dioxide. Calculate the moles of water and subtract from the initial moles of carbon dioxide to account for the moles of hydrogen and oxygen.
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
We need 14,8 g oxygen.
There are approximately 38 grams of sugar in a 12 oz can of Sprite.
38 grams