To completely react with 0.65 g of H2 to produce HCl we need 23.08 g chlorine.
63.3 g
2
how many grams of hydrogen are required to completely saturate 75 grams oleic acid which has one double bond ?
3 grams
112
6
63.3 g
2
how many grams of hydrogen are required to completely saturate 75 grams oleic acid which has one double bond ?
800 g oxygen are needed.
3 grams
112
The balanced chemical equation for the reaction between calcium and chlorine gas to produce calcium chloride is: Ca + Cl2 -> CaCl2. From this equation, we can see that one mole of calcium reacts with one mole of chlorine gas to produce one mole of calcium chloride. The molar mass of calcium is 40.08 g/mol and the molar mass of chlorine gas is 70.90 g/mol. This means that 10.0 grams of calcium is equivalent to 0.249 moles of calcium and 20.0 grams of chlorine gas is equivalent to 0.282 moles of chlorine gas. Since the ratio of calcium to chlorine gas in the balanced chemical equation is 1:1, this means that 0.249 moles of calcium would react completely with 0.249 moles of chlorine gas, leaving an excess of 0.033 moles (or 2.34 grams) of chlorine gas. The limiting reactant in this reaction is calcium, and the maximum amount of calcium chloride that can be produced is equivalent to the number of moles of the limiting reactant, which is 0.249 moles (or 27.8 grams) of calcium chloride.
Cl2 + F2 >> 2ClF 5.00 X 10^-3 grams ClF (1mol ClF/54.45g )(1mol Cl2/2mol ClF )(70.9g Cl2/1mol Cl2 ) 3.25 X 10^-3 grams of chlorine gas
16g
This question can not be answered, not even by your teacher: not enough correct information." How many grams (of WHAT ?) would 29.48 L of chlorine gas produce (after doing WHAT ?) "
Si + 2Cl2 --> SiCl4 24.4 grams silicon (1 mole Si/28.09 grams)(2 mole Cl2/1 mole Si)(70.9 grams/1 mole Cl2) = 123 grams chlorine needed =====================