63.3 g
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
To determine the theoretical yield of chromium produced, you first need to balance the chemical equation for the reaction between Cr2O3 and aluminum. Next, calculate the molar mass of Cr2O3 to find the moles used in the reaction. Use the stoichiometry of the balanced equation to find the moles of chromium that can be produced, and then convert that to grams.
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
To find the total mass of CaO that reacts with 88 grams of CO2 to produce 200 grams of CaCO3, we first need to calculate the molar mass of CaCO3 and CO2, then determine the moles of each reactant involved in the reaction. Finally, we use the stoichiometry of the reaction to find the mass of CaO required to react completely with 88 grams of CO2.
To determine the amount of chromium (III) oxide (Cr2O3) needed to produce 421 g of chromium (III) sulfide (Cr2S3), you need to consider the molar ratio of the reactants. The molar mass of Cr2S3 is 256.16 g/mol, and Cr2O3 has a molar mass of 151.99 g/mol. First, calculate the moles of Cr2S3 produced from 421 g. Then, use the molar ratio from the balanced chemical equation to find the moles of Cr2O3 needed, and convert this to grams.
800 g oxygen are needed.
To produce 4 grams of table salt (NaCl), you would need 2 moles of Na and 1 mole of Cl2. This corresponds to 46 grams of Na and 71 grams of Cl2. This would total 117 grams of reactants (2Na + Cl2) to produce 4 grams of NaCl.
You need 0,9 glucose.
4.00 grams of magnesium oxide is composed of 2.43 grams of magnesium (Mg) and 1.57 grams of oxygen (O). Therefore, to produce 4.00 grams of magnesium oxide, you would need 2.43 grams of magnesium.
To determine the theoretical yield of chromium produced, you first need to balance the chemical equation for the reaction between Cr2O3 and aluminum. Next, calculate the molar mass of Cr2O3 to find the moles used in the reaction. Use the stoichiometry of the balanced equation to find the moles of chromium that can be produced, and then convert that to grams.
To produce 1 mole of chloroform, you need 3 moles of chlorine. So, to produce 1.5 moles of chloroform, you would need 4.5 moles of chlorine. Converting moles to grams by using the molar mass of chlorine (35.5 g/mol) gives you 160.5 grams of chlorine required.
About 245 grams.
394.794 grams
To produce 1 gram of DDT, 3.3 grams of chloral are needed. Therefore, to produce 10.5 grams of DDT, you would need 10.5 * 3.3 = 34.65 grams of chloral.
To find the total mass of CaO that reacts with 88 grams of CO2 to produce 200 grams of CaCO3, we first need to calculate the molar mass of CaCO3 and CO2, then determine the moles of each reactant involved in the reaction. Finally, we use the stoichiometry of the reaction to find the mass of CaO required to react completely with 88 grams of CO2.
For the reaction 2H₂ + O₂ → 2H₂O, we know that the molar ratio of H₂ to O₂ is 2:1. To produce 900 grams of water, we need 450 grams of hydrogen (900g / 2). Therefore, we need to add 450 grams of hydrogen to 800 grams of oxygen to produce 900 grams of water.