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What is the total mass of CaO that reacts completely with 88 grams of CO2 to produce 200 grams of CaCO3?
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∙ 12y ago
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Wiki User
∙ 12y ago
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How many grams of CaCO3 form if 155g of water reacts?
Reacts with what? You need CO2 and you need a calcium source
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
How many grams of the product form when 22.4 of completely reacts?
You need to be more specific, but in general if 22.4g react completely then 22.4g are formed.
How many grams of calcium carbonate are needed to produce 95.0 L of carbon dioxide?
In 95.0 liters of CO2, there are 3.98 moles of CO2. This is determined from the molar mass of CO2 (44.010 g/mol) and that in 95.0 liters, there is .175 kg. (Density of CO2 is .001842 g/cm3) The stoichiometric equation to produce CO2 from CaCO3 is CaCO3 -> CaO + CO2. Because the equation is balanced with all coefficients being 1, it takes an equivalent number of moles of CaCO3 to produce the CO2. 3.98 moles of CaCO3 = 398 grams. (Molar weight of calcium carbonate is 100.1 g/mol)
Calculate the number of grams in these quantities 125kg CaCO3?
Just 125 kg of CaCO3 contains 125000 grams of the substance. I kilogram of any substance is equivalent to 1000 grams of it.
How many grams of CaCO3 form if 155g of water reacts?
Reacts with what? You need CO2 and you need a calcium source
How many grams of calcium carbonate are needed to produce 55.0 L of carbon dioxide at STP?
mass of CaCO3 = 246 grams
What mass of water would a ton of calcium carbonate produce if it was fully reacted with hydrochloric acid?
CaCO3 + 2HCl -> CaCl2 + CO2 + H2O 1 tonne = 2000 lbs ( I guess this is what you mean ) 2000 lbs CaCO3 (454 grams/1 lb)(1 mole CaCO3/100.09 grams)(1 mole H2O/1 mole CaCO3)(18.016 grams/1 mole H2O) = 163438.1856 grams of water ---------------------------- 163438.1856 grams (1 lb/454 grams) = 360 pounds of water -------------------------------
What is the total mass of water formed when 8 grams of hydrogen reacts completely with 64 grams of ovygen?
43.2 grams of water
How many moles are there in 250 g of CaCO3?
250 grams CaCO3 (1 mole CaCO3/100.09 grams) = 2.50 moles of calcium carbonate
How many grams of oxygen will be required to reacts completely with 0.3 moles of aluminium?
999 g
How many grams of the product form when 22.4 of completely reacts?
You need to be more specific, but in general if 22.4g react completely then 22.4g are formed.
How many grams of H2O are made when 0.240 mol of methane reacts completely with oxygen?
The answer is 8,64 g.
How many o atoms are present in 50gram of caco3?
50 grams CaCO3 (1 mole CaCO3/100.09 grams)(6.022 X 1023/1 mole CaCO3) = 3.0 X 1023 atoms of calcium carbonate =============================
How many grams of calcium carbonate are needed to produce 95.0 L of carbon dioxide?
In 95.0 liters of CO2, there are 3.98 moles of CO2. This is determined from the molar mass of CO2 (44.010 g/mol) and that in 95.0 liters, there is .175 kg. (Density of CO2 is .001842 g/cm3) The stoichiometric equation to produce CO2 from CaCO3 is CaCO3 -> CaO + CO2. Because the equation is balanced with all coefficients being 1, it takes an equivalent number of moles of CaCO3 to produce the CO2. 3.98 moles of CaCO3 = 398 grams. (Molar weight of calcium carbonate is 100.1 g/mol)
Calculate the number of grams in these quantities 125kg CaCO3?
Just 125 kg of CaCO3 contains 125000 grams of the substance. I kilogram of any substance is equivalent to 1000 grams of it.
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
