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What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of CaCO3 is 73.4kg?
To find the number of moles in 73.4 kg of CaCO3, we first need to calculate the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. Converting 73.4 kg to grams gives 73,400 g. Dividing 73,400 g by the molar mass of CaCO3 gives approximately 733 moles.
What is the mass of 0.5 moles of calcium carbonate (CaCO3)?
The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.
How do you solve for how many grams are in 2.38 moles of calcium carbonate?
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
How many moles are in 10.10 g of calcium carbonate?
To determine the number of moles in 10.10 g of calcium carbonate, we first need to find the molar mass of CaCO3, which is 40.08 g/mol for calcium, 12.01 g/mol for carbon, and 16.00 g/mol for oxygen. Adding these up gives a molar mass of 100.09 g/mol for CaCO3. Dividing 10.10 g by the molar mass gives 0.101 moles of calcium carbonate.
When calcium carbonate decomposes according to the equation caco3-cao CO2 how many grams of CO2 are produced from the decomposition of 520 g of caco3?
To find the grams of CO2 produced from the decomposition of 520 g of CaCO3, we first need to calculate the molar mass of CaCO3, which is 100.09 g/mol. This means 520 g of CaCO3 is equal to 5.19 moles. From the balanced chemical equation, 1 mole of CaCO3 produces 1 mole of CO2. Therefore, 5.19 moles of CaCO3 will produce 5.19 moles of CO2 which is equal to 235.10 g of CO2.
How many moles are in 250 g iron (III) oxide?
250 g iron (III) oxide is equal to 1,565 moles.
What is the grams of substance in 4.5 moles CaCO3?
Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that 1 mole CaCO3 = 66.1221g CaCO3. To find the mass of 4.5 mole CaCO3, complete the following calculation: 4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
How many moles of CaCO3 is 73.4kg?
To find the number of moles in 73.4 kg of CaCO3, we first need to calculate the molar mass of CaCO3. The molar mass of CaCO3 is 100.09 g/mol. Converting 73.4 kg to grams gives 73,400 g. Dividing 73,400 g by the molar mass of CaCO3 gives approximately 733 moles.
What is the mass of 0.5 moles of calcium carbonate (CaCO3)?
The molar mass of calcium carbonate (CaCO3) is approximately 100.09 g/mol. To find the mass of 0.5 moles of CaCO3, you would multiply the molar mass by the number of moles: 0.5 moles x 100.09 g/mol = 50.045 g. Therefore, the mass of 0.5 moles of calcium carbonate is 50.045 grams.
How do you solve for how many grams are in 2.38 moles of calcium carbonate?
To convert moles to grams, you need to use the molar mass of calcium carbonate (CaCO3). The molar mass of CaCO3 is approximately 100.1 g/mol. To calculate the grams in 2.38 moles of CaCO3, you would multiply the number of moles (2.38) by the molar mass (100.1 g/mol), which gives you approximately 238 grams.
How many moles are in 10.10 g of calcium carbonate?
To determine the number of moles in 10.10 g of calcium carbonate, we first need to find the molar mass of CaCO3, which is 40.08 g/mol for calcium, 12.01 g/mol for carbon, and 16.00 g/mol for oxygen. Adding these up gives a molar mass of 100.09 g/mol for CaCO3. Dividing 10.10 g by the molar mass gives 0.101 moles of calcium carbonate.
How many grams are in 2.8 moles of calcium carbonate?
2,8 moles of calcium carbonate have 240,208 g.
What is the mass of 0.5 mole of CaCO3?
The molar mass of CaCO3 is approximately 100.09 g/mol. Therefore, the mass of 0.5 moles of CaCO3 would be 50.045 g.
How many grams of CaCl2 can be obtained if 14.6 g HCl is allowed to react with excess CaCO3?
The balanced chemical equation for the reaction between HCl and CaCO3 is: 2HCl + CaCO3 → CaCl2 + H2O + CO2. The molar ratio between HCl and CaCl2 is 2:1. Calculate the number of moles of HCl from 14.6 g, then use the mole ratio to find the moles of CaCl2. Finally, convert moles of CaCl2 to grams.
Calculate the number of moles in 27.50 grams CaCO3?
To calculate the number of moles in 27.50 grams of CaCO3, you need to divide the given mass by the molar mass of CaCO3. The molar mass of CaCO3 is approximately 100.09 g/mol. So, 27.50 grams divided by 100.09 g/mol gives you approximately 0.275 moles of CaCO3.
Calculate the volume of CO2 produced at STP from the decomposition of 152 g calcium carbonate caco3?
Molar mass CaCO3 = 100.087 g/mol Moles CaCO3 = 152 g / 100.087 = 1.52 the ratio between CaCO3 and CO2 is 1 : 1 so we get 1.52 moles of CO2 At STP p=1 ATM and T = 273 K V = nRT / p = 1.52 x 0.0821 x 273 /1 = 34.1L
