Molar mass of CaCO3 = 66.1221g CaCO3/mole CaCO3. This means that
1 mole CaCO3 = 66.1221g CaCO3.
To find the mass of 4.5 mole CaCO3, complete the following calculation:
4.5g CaCO3 X 1mol CaCO3/66.1221g CaCO3 = 0.068 mole CaCO3.
45 g water are obtained.
To find the number of atoms in 45 grams of Pb (lead), we need to first calculate the number of moles. The molar mass of Pb is approximately 207.2 g/mol. By dividing the given mass by the molar mass, we can find the number of moles. Then, we can convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol).
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
0.045 grams is 45 milligrams.
45mL of plain water has a mass of about 45 grams.
45/94.2 is 0.4777 moles
To calculate the number of grams in 2.50 moles of H2O, you first need to know the molar mass of water (H2O), which is approximately 18.015 g/mol. Then, you can use the formula: grams = moles x molar mass. So, 2.50 moles of H2O is equivalent to 45.04 grams (2.50 moles x 18.015 g/mol).
45 g water are obtained.
The chemical equation for the combustion of glucose is C6H12O6 + 6O2 -> 6CO2 + 6H2O. From this, we can see that 1 mole of glucose produces 6 moles of CO2. Therefore, 45 grams of glucose (which is approximately 0.25 moles) would produce 6 times that amount of CO2, which is about 90 grams.
C6H12O6 + 6O2 --> 6CO2 + 6H2O 45 grams C6H12O6 (1 mole C6H12O6/180.156 grams)(6 moles CO2/1 mole C6H12O6)(44.01 grams/1 mole CO2) = 66 grams carbon dioxide produced ==========================
To find the number of atoms in 45 grams of Pb (lead), we need to first calculate the number of moles. The molar mass of Pb is approximately 207.2 g/mol. By dividing the given mass by the molar mass, we can find the number of moles. Then, we can convert moles to atoms using Avogadro's number (6.022 x 10^23 atoms/mol).
45 grams is approximately 0.0992 pounds
45 grams is 1.59 ounces.
Depends. It is 100% of 45 grams, 50% of 90 grams, 300% of 15 grams.
No, 45g is not equal to 50mL. Grams and milliliters are different units of measurement. Grams measure mass or weight, while milliliters measure volume. To determine if 45g is equal to 50mL, you would need to know the density of the substance being measured.
45 grams H20 x (1 mole H20/18 grams H2O) x (6.02E23 molecules H20/1 mole H2O) the grams H2O and moles H2O cancel out. When you punch it into your calculator, the answer comes out to: =1.505E24 molecules H2O
The balanced chemical equation for the combustion of glucose (C6H12O6) is: C6H12O6 + 6O2 -> 6CO2 + 6H2O. From the equation, we can see that 1 mol of C6H12O6 produces 6 mol of CO2. First, calculate the number of moles of C6H12O6 in 45 g. Then use the mole ratio to find the moles of CO2 produced, and finally convert that to grams.