92.4 grams
I think 92.4 grams
This depends on the chemical compound.
6.5 grams CO2 divided by 44 grams CO2 per mole CO2 = 6.8 mole CO2 (Molar mass CO2 = 12 + 2*16 = 44 g/mol)
First find the moles of CO2 by dividing 22 grams by the molecular weight of CO2(44.01g/mol) 22.0gCO2 1mole/44.01g CO2 = .50 molesCO2
SrCl2 Strontium (Sr) = 87.62 grams/mol 2 Chlorine (Cl) = 70.9 grams/mol ----------------------------------------------------add Strontium chloride = 158.52 grams/mol ============================
I think 92.4 grams
92.4- Nova Net
99
1.3 mole C2H2 will produce 2.6 mole CO2, weighting 2.6(mol) x 44 (g/mol) = 114 g CO2
CaC12
This depends on the chemical compound.
6.5 grams CO2 divided by 44 grams CO2 per mole CO2 = 6.8 mole CO2 (Molar mass CO2 = 12 + 2*16 = 44 g/mol)
[ 34.3(gC3H8) / 44(g/mol C3H8)] * [ 3mol CO2 / 1molC3H8 ] * 44(g/mol CO2) = 103 gram CO2
44 grams of CO2 (1 mol CO2 from 1 mol C if enough oxygen, air, is available)
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
First find the moles of CO2 by dividing 22 grams by the molecular weight of CO2(44.01g/mol) 22.0gCO2 1mole/44.01g CO2 = .50 molesCO2
How many moles of CO2 are produced when 2.1 mol of C2H2 react?