Atomic Mass of C = 14g/mol
Atomic mass of O = 16g/mol
Molecular mass of CO2 = 12 + 2(16) = 44g/mol
mass = number of moles x molecular mass
mass = 3 mol x 44g/mol = 132g
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
For every 2 moles of O2 produced, 3 moles of CO2 are used in the reaction. So you need to calculate the moles of O2 produced first using its molar mass, then use the mole ratio to find the moles of CO2 used. Finally, convert the moles of CO2 to grams using its molar mass.
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.
The balanced chemical equation for the combustion of acetylene is: 2C2H2 + 5O2 → 4CO2 + 2H2O. This means 2 moles of C2H2 produce 4 moles of CO2. Therefore, 1.3 moles of C2H2 will produce 2.6 moles of CO2, which is equivalent to approximately 84.8 grams of CO2.
Apply the equation moles -= mass(g) / Mr Algebraically rearrange mass(g) = Moles X Mr We have 2 moles Mr(CO2) = 44 ( 12 + (2 x 16) = 44) Hence substituting mass(g) = 2moles X 44 mass = 88 grams.
5.0 grams CO2 (1mol CO2/44.01g) = 0.11 moles CO2
To find the number of moles in 6.5 grams of CO2, you first need to calculate the molar mass of CO2, which is 44.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 6.5 grams / 44.01 g/mol = 0.148 moles of CO2.
To determine the grams of CO2 produced from 2.5 moles of O2, we first need to consider the balanced chemical equation for the combustion of a hydrocarbon (e.g., methane): CH4 + 2O2 → CO2 + 2H2O. From this equation, 2 moles of O2 produce 1 mole of CO2. Therefore, 2.5 moles of O2 would produce 1.25 moles of CO2. Since the molar mass of CO2 is approximately 44 grams/mol, 1.25 moles of CO2 corresponds to 55 grams (1.25 moles × 44 g/mol).
To calculate the grams of CO2 produced by burning 22 grams of C3H8, first determine the moles of C3H8 using its molar mass, then use the balanced chemical equation for the combustion of C3H8 to find the moles of CO2 produced, and finally convert moles of CO2 to grams using the molar mass of CO2.
For this reaction, the stoichiometry indicates that 4 moles of CO2 are produced for every 2 moles of C2H2 reacted. The molar mass of CO2 is approximately 44 g/mol. Therefore, you can calculate the mass of CO2 produced by converting the moles of CO2 into grams.
For this you need the atomic (molecular) mass of CO2. Take the number of grams and divide it by the atomic mass. Multiply by one mole for units to cancel. CO2=44.0 grams454 grams CO2 / (44.0 grams) = 10.3 moles CO2
The answer is 3,99 moles of carbon dioxide.
To calculate the number of moles in 42 grams of CO2, we first need to find the molar mass of CO2, which is approximately 44 grams per mole. Then, divide the given mass by the molar mass to find the number of moles. In this case, 42 grams of CO2 is equivalent to 42/44 = 0.955 moles.
The answer is 3,99 moles of carbon dioxide.
For every 2 moles of O2 produced, 3 moles of CO2 are used in the reaction. So you need to calculate the moles of O2 produced first using its molar mass, then use the mole ratio to find the moles of CO2 used. Finally, convert the moles of CO2 to grams using its molar mass.
To calculate the mass of CO2 produced from 128.00 g of O2, you need to use the balanced chemical equation for the reaction. The molar ratio between O2 and CO2 is 1:2, so if you have 128.00 g of O2, you can calculate the mass of CO2 produced by first converting grams of O2 to moles, then using the mole ratio to find the moles of CO2, and finally converting moles of CO2 to grams.
To calculate the amount of CO2 produced when burning 34.3 grams of C3H8 (propane), you need to balance the chemical equation for the combustion of C3H8. Since each mole of C3H8 produces 3 moles of CO2, you first convert 34.3 grams of C3H8 to moles, calculate the moles of CO2 produced, and then convert that to grams of CO2.