0
Apply the equation
moles -= mass(g) / Mr
Algebraically rearrange
mass(g) = Moles X Mr
We have
2 moles
Mr(CO2) = 44 ( 12 + (2 x 16) = 44)
Hence substituting
mass(g) = 2moles X 44
mass = 88 grams.
What else can I help you with?
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many moles of carbon dioxide are in 418 grams of the compound?
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
How many moles of oxygen atoms are there in 100.0 moles of carbon dioxide?
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
The are 6 grams of carbon and 20 grams of oxygen if 22 grams of carbon dioxide are produced and all the carbon is used how many grams of oxygen are left?
If 12 grams of carbon were used to form the 22 grams of carbon dioxide, this implies that 12 grams of oxygen were consumed in the reaction. Since 20 grams of oxygen were initially available, only 8 grams of oxygen are left unused.
When methane is burned with oxygen the products are carbon dioxide and water If you produce 18 grams of water from 8 grams of methane and 32 grams of oxygen how many grams of carbon dioxide were pr?
To find the grams of carbon dioxide produced, start by calculating the moles of each reactant using their molar masses. Then determine the limiting reactant (the one that forms less product). In this case, oxygen is the limiting reactant. Use the mole ratio from the balanced chemical equation to find the moles of carbon dioxide produced. Finally, convert moles of carbon dioxide to grams using its molar mass.
How many moles of carbon dioxide are there in 19 grams of carbon dioxide?
To calculate the number of moles of carbon dioxide in 19 grams, divide the given mass by the molar mass of carbon dioxide, which is approximately 44 grams/mol. Therefore, 19 grams of carbon dioxide is equal to 19/44 ≈ 0.43 moles.
How many moles of carbon are there from the original sample of 11.0 grams of carbon dioxide and 4.50 grams of water with a combustion of 7.50 grams?
Look up the molecular weight of carbon dioxide in the periodic table. The formula for carbon dioxide is CO2, which means one atom of carbon and two atoms or oxygen per molecule of carbon dioxide. Carbon has molecular weight of 12. Oxygen molecular weight is 16. Total 12+16+16= 44 11 grams/44 grams/mole=0.25 moles of carbon The grams of water and combustion of 7.5 grams are totally irrelevant. They are only given to possibly confuse you.
How many grams of carbon dioxide are needed to produce 125 grams of urea?
To produce 1 mole of urea, 1 mole of carbon dioxide is needed. The molar mass of urea is 60 grams/mol, and the molar mass of carbon dioxide is 44 grams/mol. Therefore, to produce 125 grams of urea, 125 grams/60 grams/mol = 2.08 moles of urea is needed. This means 2.08 moles of carbon dioxide is needed, which is 2.08 moles * 44 grams/mol = 91.52 grams of carbon dioxide needed.
How many moles of co2 form when 58 grams of butane burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
How many moles of carbon dioxide are in 418 grams of the compound?
The molar mass of carbon dioxide is 44.01 g/mol (12.01 g/mol for carbon + 2 * 16.00 g/mol for oxygen). To find the number of moles in 418 grams, divide 418 grams by the molar mass of carbon dioxide. The calculation is 418 g / 44.01 g/mol = 9.50 moles of carbon dioxide.
How many moles of CO2 form when 58 grams of butane C4H10 burn in oxygen?
The answer is 3,99 moles of carbon dioxide.
How many moles of carbon dioxide are there in 211g of carbon dioxide?
211g of carbon dioxide are equal to 4,794 moles.
How many moles are in 85.636 grams of carbon?
85.636 grams carbon (1 mole C/12.01 grams) = 7.1304 moles of carbon ---------------------------------
How many moles are in 66 grams of carbon dioxide?
To calculate the number of moles in 66 grams of carbon dioxide, we need to divide the given mass by the molar mass of carbon dioxide. The molar mass of carbon dioxide is approximately 44 grams per mole. Therefore, 66 grams of carbon dioxide is equal to 66/44 ≈ 1.5 moles.
How many moles of carbon are in 0.100 moles of carbon dioxide?
0.1 moles There is one carbon and two oxygens 1 x 0.1 = 0.1
How many moles of oxygen atoms are there in 100.0 moles of carbon dioxide?
There are twice as many oxygen atoms as carbon atoms in carbon dioxide, so 100.0 moles of carbon dioxide would contain 200.0 moles of oxygen atoms.
How many moles of carbon dioxide is present in 220mg?
First, convert the mass of carbon dioxide to grams by dividing by 1000: 220 mg = 0.22 g. Next, use the molar mass of carbon dioxide (44 g/mol) to calculate the number of moles: 0.22 g / 44 g/mol = 0.005 moles of carbon dioxide.
