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42.1g/ 59g/mol (grams/molar mass of C3H8O)
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
1654 grams exactly
200 molecules C3H8O (1 mole C3H8O/6.022 X 10^23)(3 mole C/1 mole C3H8O)(6.022 X 10^23/1 mole C) = 600 molecules of carbon atoms -------------------------------------------- Of course, you can just look at this set up and see there are 600 molecules. My answer set up is a formal set up. ( 200 * 3 would do it )
32,895 g of triuraniumoctaoxide (U3O8).
42.1g/ 59g/mol (grams/molar mass of C3H8O)
there would be 50 grams of ammonia will be formed
C3H8O ==== Count them.
C3H8O ==== Count them.
25
how many grams of oxygen are consumed when 19.4g of carbon dioxide is formed during the combustion of C7H16
There is no mass loss (nor gain) in state change, so there would be 100 grams of ice formed.
5a+10b = 10ab
99.8gS
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
Given the balanced equation2C3H8O + 9O2 --> 6CO2 + 8H2OTo find the number of moles CO2 that will be produced from 0.33 mol C3H8O, we must convert from moles to moles (mol --> mol conversion).0.33 mol C3H8O * 6 molecules CO2 = 0.99 mol CO2---------- 2 molecules C3H8O
234 grams