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The charge passing through the cell is 15 x 10 x 60 = 9000 coulombs. No. of electrons = 0.0935 mole e- Since nickel has a charge of +2, one atom of nickel will require 2 e- to plate So, 0.0935 mole e- will give 0.0935/2 = 0.04675 mole e- of Nickel. Then one can calculate the no. of gms of nickel that can be plated out.

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Q: How many grams of nickel metal are plated out when a constant current of 15.0 A is passed through aqueous NICl2 for 10.0 minutes?
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