You can't answer this question unless you know the the NO2 was formed FROM. You need to write the balanced reaction for the reaction and then use stoichiometry to solve for the amount of oxygen produce.
See the Related Questions to the left for how to write a balanced reaction and how to use stoichiometry to solve this type of problem.
The molar mass of NO2 is 46.01 grams per mole, so there is .25 moles of NO2. This means there is also .25 moles of O2 which is equal to 7.999 grams.
No one can answer your question since you haven't shown the reaction equation. The reaction equation is needed so that the ratio of oxygen to nitrous oxide is known.
2 grams of O2
66g
888
49.7g O2
the same amount would have to stay in grams, so if 14 grams of nitrogen is formed, then 8 grams of oxygen, add those two together and you get 22. and that's 22 of the 40 grams used, so 40 subtracted by 22 is 18. 18 grams of water would be formed.
11 grams because all is reacted and there is no reactant left over, although if there were only 3 grams of carbon there would have to be 6 grams of oxygen for this to be viable as carbon dioxide is CO2 so the question asked was itself wrong.
When the amount of oxygen is limited, carbon and oxygen react to form carbon monoxide. How many grams of CO can be formed from 35 grams of oxygen?
how many grams of oxygen are consumed when 19.4g of carbon dioxide is formed during the combustion of C7H16
25
The answer is 6,992 g oxygen.
61,27 carbon monoxide are formed.
66g
67.5 grams of H2O
Six oxygen molecules are released when one glucose molecule is formed.
i dont know help :C
22 grams carbon dioxide (0.5 moles)
The answer is 165,5 g water.
Two moles of water are produced.