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in first step prepare ethane to chloro ethane fallowed by wurtz reaction. chloro ethane can be prepared free radical reaction btw ethane and chlorine
C2h6+7o=2co2+3h2o
You are trying to reduce ethane to ethene, I am guessing. That is a very hard reaction to do... probably you will have to do a free radical halogenation on ethane to form 1-chloroethane, followed by an E2 reaction with t-butoxide or some other bulky base to form ethene. Since ethane and ethene are both gases and cheaply available from petroleum cracking, this reaction really isn't worth doing.
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.
The chemical reaction when C2H6 gas (ethane) is combusted is: 2C2H6 + 7O2 -> 4CO2 + 6H2O. Ethane reacts with oxygen to produce carbon dioxide and water.
in first step prepare ethane to chloro ethane fallowed by wurtz reaction. chloro ethane can be prepared free radical reaction btw ethane and chlorine
C2h6+7o=2co2+3h2o
ethane + Oxygen --> Carbon dioxide + Water
UV Light
CH4 + Cl2 = CH3Cl + HCl (in presence of sun light) CH3Cl + Na/ether = CH3-CH3 + NaCl (ethane) this reaction is called wurtz reaction.........
Rust it is an oxide, formed by the reaction with oxygen or oxygenated water ; ethane don't react with water.
You are trying to reduce ethane to ethene, I am guessing. That is a very hard reaction to do... probably you will have to do a free radical halogenation on ethane to form 1-chloroethane, followed by an E2 reaction with t-butoxide or some other bulky base to form ethene. Since ethane and ethene are both gases and cheaply available from petroleum cracking, this reaction really isn't worth doing.
I am presuming that you are asking how many carbon dioxide (CO2) molecules will be formed when two ethane (C2H6) molecules burn in a plentiful supply of oxygen. The following balanced equation is that of the burning of ethane in a plentiful supply of oxygen: C2H6 + 3.5O2 -----> 2CO2 + 3H2O. The number before each of the molecules in the equation tells us how many there are in this reaction. This means that for every one ethane molecule that is burnt, two carbon dioxide molecules are produced.
The chemical reaction when C2H6 gas (ethane) is combusted is: 2C2H6 + 7O2 -> 4CO2 + 6H2O. Ethane reacts with oxygen to produce carbon dioxide and water.
Combustion of Ethane: 2C2H6+7O2-->4CO2+6H2O Combustion of Ethanol: C2H5OH+3O2-->2CO2+3H2O
You think probable to polymerization.
Monohalogenation of methane, followed by Wurtz reaction.